我已经实现了RavenDB Denormalized Reference模式。我正在努力将静态索引和补丁更新请求连接在一起,以确保在更改引用的实例值时更新我的非规范化引用属性值。
这是我的域名:
public class User
{
public string UserName { get; set; }
public string Id { get; set; }
public string Email { get; set; }
public string Password { get; set; }
}
public class UserReference
{
public string Id { get; set; }
public string UserName { get; set; }
public static implicit operator UserReference(User user)
{
return new UserReference
{
Id = user.Id,
UserName = user.UserName
};
}
}
public class Relationship
{
public string Id { get; set; }
public UserReference Mentor { get; set; }
public UserReference Mentee { get; set; }
}
您可以看到UserReference包含引用的User的Id和UserName。所以现在,如果我更新给定User实例的UserName,那么我希望所有UserReferences中引用的Username值也更新。为实现这一点,我编写了一个静态索引和一个补丁请求,如下所示:
public class Relationships_ByMentorId : AbstractIndexCreationTask<Relationship>
{
public Relationships_ByMentorId()
{
Map = relationships => from relationship in relationships
select new {MentorId = relationship.Mentor.Id};
}
}
public static void SetUserName(IDocumentSession db, User mentor, string userName)
{
mentor.UserName = userName;
db.Store(mentor);
db.SaveChanges();
const string indexName = "Relationships/ByMentorId";
RavenSessionProvider.UpdateByIndex(indexName,
new IndexQuery
{
Query = string.Format("MentorId:{0}", mentor.Id)
},
new[]
{
new PatchRequest
{
Type = PatchCommandType.Modify,
Name = "Mentor",
Nested = new[]
{
new PatchRequest
{
Type = PatchCommandType.Set,
Name = "UserName",
Value = userName
},
}
}
},
allowStale: false);
}
最后一个UnitTest失败,因为更新没有按预期工作。
[Fact]
public void Should_update_denormalized_reference_when_mentor_username_is_changed()
{
using (var db = Fake.Db())
{
const string userName = "updated-mentor-username";
var mentor = Fake.Mentor(db);
var mentee = Fake.Mentee(db);
var relationship = Fake.Relationship(mentor, mentee, db);
db.Store(mentor);
db.Store(mentee);
db.Store(relationship);
db.SaveChanges();
MentorService.SetUserName(db, mentor, userName);
relationship = db
.Include("Mentor.Id")
.Load<Relationship>(relationship.Id);
relationship.ShouldNotBe(null);
relationship.Mentor.ShouldNotBe(null);
relationship.Mentor.Id.ShouldBe(mentor.Id);
relationship.Mentor.UserName.ShouldBe(userName);
mentor = db.Load<User>(mentor.Id);
mentor.ShouldNotBe(null);
mentor.UserName.ShouldBe(userName);
}
}
一切运行正常,索引在那里,但我怀疑这不会返回补丁请求所需的关系,但老实说,我已经没有人才了。你能帮帮忙吗?
修改1
@MattWarren allowStale=true
没有帮助。但是我注意到了一个潜在的线索。
因为这是一个单元测试我使用的是InMemory,嵌入式IDocumentSession - 上面代码中的Fake.Db()
。然而,当调用静态索引时,即在执行UpdateByIndex(...)
时,它使用通用IDocumentStore,而不是特定的伪IDocumentSession。
当我更改索引定义类然后运行单元测试时,索引会在“真实”数据库中更新,并且可以通过Raven Studio查看更改。但是,“保存”到InMemory数据库中的伪域实例(mentor
,mentee
等)不会存储在实际数据库中(如预期的那样),因此无法通过Raven Studio查看。
可能是我对UpdateByIndex(...)
的调用是针对错误的IDocumentSession运行的,“真正的”(没有保存的域实例),而不是假的?
编辑2 - @Simon
我已针对上面编辑1中列出的问题实施了修复,我认为我们正在取得进展。你是对的,我通过IDocumentStore
使用了对RavenSessionProvder
的静态引用。现在情况并非如此。以下代码已更新为使用Fake.Db()
代替。
public static void SetUserName(IDocumentSession db, User mentor, string userName)
{
mentor.UserName = userName;
db.Store(mentor);
db.SaveChanges();
const string indexName = "Relationships/ByMentorId";
db.Advanced.DatabaseCommands.UpdateByIndex(indexName,
new IndexQuery
{
Query = string.Format("MentorId:{0}", mentor.Id)
},
new[]
{
new PatchRequest
{
Type = PatchCommandType.Modify,
Name = "Mentor",
Nested = new[]
{
new PatchRequest
{
Type = PatchCommandType.Set,
Name = "UserName",
Value = userName
},
}
}
},
allowStale: false);
}
}
您会注意到我也重置了allowStale=false
。现在,当我运行此操作时,我收到以下错误:
Bulk operation cancelled because the index is stale and allowStale is false
我认为我们已经解决了第一个问题,现在我正在使用正确的Fake.Db,我们遇到的问题首先突出显示,索引是陈旧的,因为我们在单元测试中运行超快。
现在的问题是:如何使UpdateByIndex(..)
方法等到命令-Q为空并且索引被认为是“新鲜”?
编辑3
考虑到防止陈旧索引的建议,我更新了代码如下:
public static void SetUserName(IDocumentSession db, User mentor, string userName)
{
mentor.UserName = userName;
db.Store(mentor);
db.SaveChanges();
const string indexName = "Relationships/ByMentorId";
// 1. This forces the index to be non-stale
var dummy = db.Query<Relationship>(indexName)
.Customize(x => x.WaitForNonStaleResultsAsOfLastWrite())
.ToArray();
//2. This tests the index to ensure it is returning the correct instance
var query = new IndexQuery {Query = "MentorId:" + mentor.Id};
var queryResults = db.Advanced.DatabaseCommands.Query(indexName, query, null).Results.ToArray();
//3. This appears to do nothing
db.Advanced.DatabaseCommands.UpdateByIndex(indexName, query,
new[]
{
new PatchRequest
{
Type = PatchCommandType.Modify,
Name = "Mentor",
Nested = new[]
{
new PatchRequest
{
Type = PatchCommandType.Set,
Name = "UserName",
Value = userName
},
}
}
},
allowStale: false);
}
从上面编号的评论:
放入一个虚拟查询以强制索引等待,直到它是非陈旧的工作。消除了有关陈旧指数的错误。
这是确保我的索引正常工作的测试行。看起来很好。返回的结果是提供的Mentor.Id('users-1')的正确Relationship实例。
{ “导师”: { “Id”:“users-1”, “UserName”:“Mentor先生” }, “被指导者”:{ “Id”:“users-2”, “UserName”:“Mentee先生” } ... }
尽管索引是非陈旧的并且看似正常运行,但实际的补丁请求似乎什么也没做。 Mentor的非规范化参考中的UserName保持不变。
所以怀疑现在落在补丁请求本身上。为什么这不起作用?这可能是我设置要更新的UserName属性值的方式吗?
...
new PatchRequest
{
Type = PatchCommandType.Set,
Name = "UserName",
Value = userName
}
...
您将注意到我只是将userName
param的字符串值直接分配给Value
属性,该属性的类型为RavenJToken
。这可能是一个问题吗?
编辑4
优秀!我们有一个解决方案。我已经重新编写了代码以允许您提供的所有新信息(谢谢)。为了防止任何人真正读到这一点,我最好输入工作代码来给他们封闭:
单元测试
[Fact]
public void Should_update_denormalized_reference_when_mentor_username_is_changed()
{
const string userName = "updated-mentor-username";
string mentorId;
string menteeId;
string relationshipId;
using (var db = Fake.Db())
{
mentorId = Fake.Mentor(db).Id;
menteeId = Fake.Mentee(db).Id;
relationshipId = Fake.Relationship(db, mentorId, menteeId).Id;
MentorService.SetUserName(db, mentorId, userName);
}
using (var db = Fake.Db(deleteAllDocuments:false))
{
var relationship = db
.Include("Mentor.Id")
.Load<Relationship>(relationshipId);
relationship.ShouldNotBe(null);
relationship.Mentor.ShouldNotBe(null);
relationship.Mentor.Id.ShouldBe(mentorId);
relationship.Mentor.UserName.ShouldBe(userName);
var mentor = db.Load<User>(mentorId);
mentor.ShouldNotBe(null);
mentor.UserName.ShouldBe(userName);
}
}
假货
public static IDocumentSession Db(bool deleteAllDocuments = true)
{
var db = InMemoryRavenSessionProvider.GetSession();
if (deleteAllDocuments)
{
db.Advanced.DatabaseCommands.DeleteByIndex("AllDocuments", new IndexQuery(), true);
}
return db;
}
public static User Mentor(IDocumentSession db = null)
{
var mentor = MentorService.NewMentor("Mr. Mentor", "mentor@email.com", "pwd-mentor");
if (db != null)
{
db.Store(mentor);
db.SaveChanges();
}
return mentor;
}
public static User Mentee(IDocumentSession db = null)
{
var mentee = MenteeService.NewMentee("Mr. Mentee", "mentee@email.com", "pwd-mentee");
if (db != null)
{
db.Store(mentee);
db.SaveChanges();
}
return mentee;
}
public static Relationship Relationship(IDocumentSession db, string mentorId, string menteeId)
{
var relationship = RelationshipService.CreateRelationship(db.Load<User>(mentorId), db.Load<User>(menteeId));
db.Store(relationship);
db.SaveChanges();
return relationship;
}
单元测试的Raven会话提供程序
public class InMemoryRavenSessionProvider : IRavenSessionProvider
{
private static IDocumentStore documentStore;
public static IDocumentStore DocumentStore { get { return (documentStore ?? (documentStore = CreateDocumentStore())); } }
private static IDocumentStore CreateDocumentStore()
{
var store = new EmbeddableDocumentStore
{
RunInMemory = true,
Conventions = new DocumentConvention
{
DefaultQueryingConsistency = ConsistencyOptions.QueryYourWrites,
IdentityPartsSeparator = "-"
}
};
store.Initialize();
IndexCreation.CreateIndexes(typeof (RavenIndexes).Assembly, store);
return store;
}
public IDocumentSession GetSession()
{
return DocumentStore.OpenSession();
}
}
索引
public class RavenIndexes
{
public class Relationships_ByMentorId : AbstractIndexCreationTask<Relationship>
{
public Relationships_ByMentorId()
{
Map = relationships => from relationship in relationships
select new { Mentor_Id = relationship.Mentor.Id };
}
}
public class AllDocuments : AbstractIndexCreationTask<Relationship>
{
public AllDocuments()
{
Map = documents => documents.Select(entity => new {});
}
}
}
更新非规范化参考
public static void SetUserName(IDocumentSession db, string mentorId, string userName)
{
var mentor = db.Load<User>(mentorId);
mentor.UserName = userName;
db.Store(mentor);
db.SaveChanges();
//Don't want this is production code
db.Query<Relationship>(indexGetRelationshipsByMentorId)
.Customize(x => x.WaitForNonStaleResultsAsOfLastWrite())
.ToArray();
db.Advanced.DatabaseCommands.UpdateByIndex(
indexGetRelationshipsByMentorId,
GetQuery(mentorId),
GetPatch(userName),
allowStale: false
);
}
private static IndexQuery GetQuery(string mentorId)
{
return new IndexQuery {Query = "Mentor_Id:" + mentorId};
}
private static PatchRequest[] GetPatch(string userName)
{
return new[]
{
new PatchRequest
{
Type = PatchCommandType.Modify,
Name = "Mentor",
Nested = new[]
{
new PatchRequest
{
Type = PatchCommandType.Set,
Name = "UserName",
Value = userName
},
}
}
};
}
答案 0 :(得分:4)
尝试更改行:
RavenSessionProvider.UpdateByIndex(indexName, //etc
到
db.Advanced.DatabaseCommands.UpdateByIndex(indexName, //etc
这将确保在您在单元测试中使用的相同(伪造)文档存储上发出更新命令。
回答编辑2:
使用UpdateByIndex时,没有自动等待非陈旧结果的方法。您在SetUserName
方法中有几个选择:
1 - 将数据存储区更改为始终像这样立即更新索引(注意:这可能会对性能产生负面影响):
store.Conventions.DefaultQueryingConsistency = ConsistencyOptions.MonotonicRead;
2 - 在UpdateByIndex调用之前,针对索引运行查询,指定WaitForNonStaleResults
选项:
var dummy = session.Query<Relationship>("Relationships_ByMentorId")
.Customize(x => x.WaitForNonStaleResultsAsOfLastWrite())
.ToArray();
3 - 在索引失效时捕获异常抛出,执行Thread.Sleep(100)
并重试。
回答编辑3:
我终于弄明白了,并且通过了测试...无法相信,但它似乎只是一个缓存问题。当您重新加载文档以进行断言时,您需要使用其他会话...例如
using (var db = Fake.Db())
{
const string userName = "updated-mentor-username";
var mentor = Fake.Mentor(db);
var mentee = Fake.Mentee(db);
var relationship = Fake.Relationship(mentor, mentee, db);
db.Store(mentor);
db.Store(mentee);
db.Store(relationship);
db.SaveChanges();
MentorService.SetUserName(db, mentor, userName);
}
using (var db = Fake.Db())
{
relationship = db
.Include("Mentor.Id")
.Load<Relationship>(relationship.Id);
//etc...
}
不敢相信我没有早点发现这个,抱歉。