将类的Ruby数组转换为JSON

时间:2012-04-24 06:24:57

标签: ruby json

我有一个Ruby数据结构:

class Albums
    attr_accessor :title, :url

    def initialize(title, url)
        @title = title
        @url = url
    end
end

class Albumlist < Albums
    attr_accessor :id, :albums

    def initialize(id)
        @id = id
        @albums = Array.new
    end
end

我制作了一个 Albumlist 的数组,看起来像(使用.inspect方法):

[#<Albumlist:0x8db6390 @id="abc",@albums=[
     #<Albums:0x8db6098 @title="123", @url="test">,
     #<Albums:0x8db5fe4 @title="456", @url="test">
 ]>,
 #<Albumlist:0x8f4042c @id="def", @albums=[
     #<Albums:0x8f49f2c @title="Untitled Album", @url="test">
 ]>
]

我不确定这个数组是否正常但是一旦我在这个数组上使用方法.to_json或JSON.generate(),我得到的只是:

["#<Albumlist:0x8db6390>","#<Albumlist:0x8f4042c>"]

看起来Ruby返回对象实例的“引用”。 我想用JSON转换这个数组,看起来像

[
    {
            "id":"abc"
            "albums":[
                    {
                            "title":"123",
                            "url":"test"
                    },
                    {
                            "title":"456",
                            "url":"test"
                    }
            ]
    },
    {
            "id":"def"
            "albums":[
                    {
                            "title":"Untitled Album",
                            "url":"test"
                    }
            ]
    }
]

我相信我遗漏了一些东西,例如将数组转换为某种中间对象?

编辑:替代解决方案

在类Albumlist中定义一个to_json方法:

def to_json(*a)
    {
        "id" => @id,
        "albums" => @albums
    }.to_json(*a)
end

然后使用它..

1 个答案:

答案 0 :(得分:1)

这里有效,可能你没有在正确的时刻应用这个方法,让我们试试吧,首先,用这样的东西专注于数组:

require 'rubygems'
require 'active_support/all'
class Albums
    attr_accessor :title, :url

    def initialize(title, url)
        @title = title
        @url = url
    end
end

class Albumlist < Albums
    attr_accessor :id, :albums

    def initialize(id)
        @id = id
        @albums = Array.new
    end
end

a = Albums.new("a", "www.a.com")
b = Albums.new("b", "www.b.com")
c = Albums.new("c", "www.c.com")

list_of_albums_list = Array.new
list_a = Albumlist.new(1)
list_b = Albumlist.new(2)

list_a.albums << a
list_a.albums << b
list_b.albums << c

list_of_albums_list << list_a
list_of_albums_list << list_b
puts list_of_albums_list.to_json

输出是:

[{"albums":[{"title":"a","url":"www.a.com"},{"title":"b","url":"www.b.com"}],"id":1},{"albums":[{"title":"c","url":"www.c.com"}],"id":2}]

因此该方法按预期工作。