Java / Android：将xml转换为loopable对象的最简单方法？ （地图？）

Question

我有一个包含XML内容的字符串，其结构如下。我的问题是，我如何轻松地将其转换为某种对象，然后循环遍历其中的所有项目？

是否有任何易于使用的库可以做到这一点？如果是这样，那么例子会很棒。我最近加入了Java开发，我还在学习。

我刚看过XStream（http://x-stream.github.io/tutorial.html），看起来很有希望。我只是不知道如何正确应用它。

<requests>
    <0>
        <id>1</id>
        <key>sms_number</key>
        <value>0709601159</value>
    </0>
    <1>
        <id>1</id>
        <key>sms_text</key>
        <value>This is a text message, blablabla.</value>
    </1>
</requests>

非常感谢任何建议，想法或例子。

Answer 1

创建一个定义对象内容的类：

public class Term implements Serializable {


private static final long serialVersionUID = 1L;
private String word;
private String abbr1;
private String abbr2;
private String definition;
private String formula;

public String getWord() {
    return word;
}
public void setWord(String word) {
    this.word = word;
}
public String getAbbr1() {
    return abbr1;
}
public void setAbbr1(String abbr1) {
    this.abbr1 = abbr1;
}
public String getAbbr2() {
    return abbr2;
}
public void setAbbr2(String abbr2) {
    this.abbr2 = abbr2;
}
public String getDefinition() {
    return definition;
}
public void setDefinition(String definition) {
    this.definition = definition;
}
public String getFormula() {
    return formula;
}
public void setFormula(String formula) {
    this.formula = formula;
}

}

然后使用XML解析器来解析XML：

public ArrayList<Term> getTerms(){
    ArrayList<Term> termsList = new ArrayList<Term>();

    //create array lists for the four attributes of each term
    ArrayList<String> word = new ArrayList<String>();
    ArrayList<String> abbr1 = new ArrayList<String>();
    ArrayList<String> abbr2 = new ArrayList<String>();
    ArrayList<String> definition = new ArrayList<String>();
    ArrayList<String> formula = new ArrayList<String>();

    //Strings for each of the attributes
    String currentWord = null;
    String currentAbbr1 = null;
    String currentAbbr2 = null;
    String currentDefinition = null;
    String currentFormula = null;



    //try to parse the XML into the four array lists
    try{

        //get the xml document and put it into a reader
        XmlPullParser parser = getResources().getXml(R.xml.terminology);

        //set the eventType and the boolean to test if finished.
        int eventType = parser.getEventType();
        boolean done = false;

        /*
         * while statement that will read through the xml document and includes
         * a switch case block that will go through the tags and put the attributes
         * into the appropriate array lists
         */
        while (eventType !=XmlPullParser.END_DOCUMENT && !done){
            String name = null;
            switch (eventType){
            case XmlPullParser.START_DOCUMENT:
                break;
            case XmlPullParser.START_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("terminology")){

                }else if (word != null && abbr1 != null && abbr2 != null && definition != null && formula != null){
                    if (name.equalsIgnoreCase("term")){

                    }else if (name.equalsIgnoreCase("word")){
                        currentWord = new String(parser.getAttributeValue(0));
                    }else if (name.equalsIgnoreCase("abbr1")){
                        currentAbbr1 = new String(parser.getAttributeValue(0));
                    }else if (name.equalsIgnoreCase("abbr2")){
                        currentAbbr2 = new String(parser.getAttributeValue(0));
                    }else if (name.equalsIgnoreCase("definition")){
                        currentDefinition = new String(parser.getAttributeValue(0));
                    }else if (name.equalsIgnoreCase("formula")){
                        currentFormula = new String(parser.getAttributeValue(0));
                    }
                }
                break;
            case XmlPullParser.END_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("formula") && currentFormula != null){
                    formula.add(currentFormula);
                }else if (name.equalsIgnoreCase("definition") && currentDefinition != null){
                    definition.add(currentDefinition);
                }else if (name.equalsIgnoreCase("abbr2") && currentAbbr2 != null){
                    abbr2.add(currentAbbr2);
                }else if (name.equalsIgnoreCase("abbr1") && currentAbbr1 != null){
                    abbr1.add(currentAbbr1);
                }else if (name.equalsIgnoreCase("word") && currentWord != null){
                    word.add(currentWord);
                }else if (name.equalsIgnoreCase("term")){
                }else if (name.equalsIgnoreCase("terminology")){
                    done = true;
                }
                break;  
            }
            eventType = parser.next();
        }



    }
    catch (FileNotFoundException e){

    }
    catch (IOException e){

    }
    catch (Exception e){

    }

    for (int i=0; i < word.size(); i++){
        Term term = new Term();
        term.setWord(word.get(i));
        term.setAbbr1(abbr1.get(i));
        term.setAbbr2(abbr2.get(i));
        term.setDefinition(definition.get(i));
        term.setFormula(formula.get(i));
        termsList.add(term);


    }


    return termsList;
}

这对我来说很棒。这是很多代码，但它确实有效，实际上很快。我注意到没有滞后时间，我的XML中有近30个“术语”，每个术语有5个属性。只需将您的XML存储在res / xml下（您可能需要创建XML文件夹）。

Answer 2

不是一个答案，但你也可以考虑使用Simple：http://simple.sourceforge.net/download/stream/doc/tutorial/tutorial.php#deserialize

它有一套非常易于理解的教程，如果我没记错的话，它很小，所以它不应该为你的应用程序增加太多的大小。

与大多数这些XML解析库一样，您需要创建某种数据对象来保存反序列化的数据，并且您需要在该类中添加一些标记，以便让反序列化器知道您想要的数据从XML文件中捕获以及存储它的位置。