Question

我有一系列哈希（或至少我认为它们是哈希），我需要为每个哈希取出ID。我确信ruby有一些快速的方法可以做到这一点......我无法弄明白。

我不想遍历数组并构建一个新数组。

[
  [
    {
      "bio": "I am a tech geek who loves starting up companies. While I was in college, I founded Squeeze My Tees",
      "business_name": "Rounded Development",
      "city": "",
      "created_at": "2012-04-22T18:07:44Z",
      "first_name": "Brian",
      "id": 1,
      "industry": "Entertainment",
      "last_name": "Weinreich",
      "lat": null
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:35Z",
      "email": "test@jambo.com",
      "first_name": "asdad",
      "id": 2,
      "industry": null,
      "last_name": "ddfs",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:35Z"
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:39Z",
      "email": "tesasdat@jambo.com",
      "first_name": "fdsd",
      "id": 3,
      "industry": null,
      "last_name": "asdgw",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:39Z"
    },
    {
      "access_token": null,
      "bio": null,
      "business_name": null,
      "city": null,
      "created_at": "2012-04-23T13:56:44Z",
      "email": "asdsad@jambo.com",
      "first_name": "ewtrwef",
      "id": 4,
      "industry": null,
      "last_name": "dfd",
      "lat": null,
      "linkedin_id": null,
      "linkedin_url": null,
      "lng": null,
      "position": null,
      "professional_headline": null,
      "state": null,
      "street": null,
      "updated_at": "2012-04-23T13:56:44Z"
    }
  ]
]

Answer 1

只需提取ID即可：

the_IDs = array_of_hashes.collect { |single_array| single_array["id"] }

显然，您可以使用较少的详细变量名称，它们仅用于说明。但是这个想法是你可以遍历数组并收集块返回的内容。在这种情况下，您将继续获取ID，而the_IDs将只是收集的数据的数组。

你如何从红宝石中的一系列哈希中获取一个键/值对？

1 个答案: