我有一个带有id列表的变量(例如:121,131,142,145)。其中,我想查找一个表中不存在的id列表。此查询的输出应该是不存在的id列表。如何使用单个msssql查询实现。如果id 142和145不存在于表中,则查询应返回这两个值。是否可以使用IN子句
答案 0 :(得分:3)
你需要一个分隔字符串到表转换udf,如下所示:
CREATE FUNCTION [dbo].[fnc_List2Table] (
@list varchar(8000),
@delimiter varchar(16) = ','
) RETURNS @result TABLE (
ListIndex int,
Value varchar(8000)
)
AS
BEGIN
SET @list = LTRIM(RTRIM(ISNULL(@list, SPACE(0))))
DECLARE @n int, @i int, @delimiterIndex int, @nextItem varchar(8000)
SET @n = LEN('#' + @delimiter + '#') - 2
SET @i = 0
WHILE @list <> SPACE(0)
BEGIN
SET @i = @i + 1
SET @delimiterIndex = CHARINDEX(@delimiter, @list)
IF @delimiterIndex = 0
BEGIN
SET @nextItem = LTRIM(RTRIM(@list))
SET @list = SPACE(0)
END
ELSE
BEGIN
SET @nextItem = LTRIM(RTRIM(LEFT(@list, @delimiterIndex-1)))
SET @list = RIGHT(@list, LEN(@list)-(@delimiterIndex+(@n-1)))
END
INSERT INTO @result (ListIndex, Value)
VALUES (@i, @nextItem)
END
RETURN
END
然后您可以使用左连接轻松检查ID:
declare @ids varchar(50)
set @ids = '121,131,142,145'
select F.Value
from fnc_List2Table(@ids,',') F
left join YourTable A on F.Value = A.ID
where A.ID is null
答案 1 :(得分:0)
这是另一个实现,它是来自http://www.sqlservercentral.com/articles/Tally+Table/72993/
的修改版本 CREATE FUNCTION dbo.DelimitedSplit8K
--===== Define I/O parameters
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "zero base" and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT 0 UNION ALL
SELECT TOP (DATALENGTH(ISNULL(@pString,1))) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT t.N+1
FROM cteTally t
WHERE (SUBSTRING(@pString,t.N,1) = @pDelimiter OR t.N = 0)
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY s.N1),
Item = SUBSTRING(@pString,s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000))
FROM cteStart s;
udf保留原样来自sqlservercentral文章
select a.id from
(-- simulate the id table using union queries
select 1 id union all
select 2 id union all
select 3 id union all
select 4 id union all
select 5 id union all
select 6 id union all
select 7 id union all
select 8 id union all
select 9 id union all
select 10 id union all
select 11 id
)a
LEFT JOIN -- Do the magic
(SELECT item id FROM DelimitedSplit8K( '1,2,4,5',','))b on a.id = b.Id
WHERE b.Id is null;
我使用了左连接并过滤了空值而不是IN语句