Question

我在下面的查询导致了我的问题。总而言之，因为我有不同的服务日期，它由不同的服务公司进行分组，但我只想要明确的区域接下来的总数。因为我现在很困惑，怎么能绕过这个!!!

SELECT DISTINCT(DISTRICT), 
        Sum(completed) as TotalCompleted, 
        MONTHNAME,
        MONTH

FROM( SELECT  TBL_PROPERTY.DISTRICT,
        TBL_SERVICE.SERVICEDATE, 
        DATENAME(MONTH, SERVICEDATE) AS MONTHNAME,
        CONVERT(INT,CONVERT(VARCHAR,DATEPART(YEAR, SERVICEDATE) + '00')) + DATEPART(MONTH, SERVICEDATE) AS MONTH,
        COUNT(tbl_property.Propref) AS Completed

FROM TBL_SERVICE INNER JOIN TBL_PROPERTY ON TBL_SERVICE.PROPREF = TBL_PROPERTY.PROPREF 

WHERE (TBL_PROPERTY.CONTRACT ='ma2') AND 
        (LASTSERVICEDATE BETWEEN '01/jun/2009' AND DATEADD(hh,23,'15/jun/2009')) AND 
        (NOT (TBL_SERVICE.BILLCODE1 = 'NA')) AND  
        (TBL_SERVICE.STATUS = 'Serviced') AND 
        (PROPERTYCLASS = 'cont') 

GROUP BY DISTRICT, servicedate
) As sub1

GROUP BY DISTRICT, monthname, month, Completed

示例数据

例如，我目前看到

区1 - 2 - 6月 1区 - 5区 - 6月

我想看看

1区 - 7月 - 6月

Answer 1

如果我正确地读了你，你只想看DISTRTICT，SUM（COMPLETED）。如果是这种情况，你应该

 SELECT DISTRTICT, SUM(COMPLETED) FROM...

并在最后

 GROUP BY DISTRICT

修改

根据您的更新请求，我建议您执行以下操作：

SELECT DISTRTICT, SUM(COMPLETED), MONTHNAME FROM...

并在最后

GROUP BY DISTRICT, MONTHNAME

Answer 2

我没有仔细检查过，但看起来你的问题是你已经“完成”，这是你最后在GROUP BY中的聚合。

将最后一行更改为如下所示，看看是否有效。

GROUP BY DISTRICT, monthname, month

子查询问题

2 个答案: