Question

我有以下表格：

内容：content_id，user_id，post_date

评论：comment_id，user_id，comment_date

如何获得按月和年分组的活跃唯一身份用户数？ Active表示用户在该月份发布或评论。

Answer 1

SELECT
  T.action_year,
  T.action_month,
  COUNT(T.user_id) active_users
FROM
  (
  SELECT DISTINCT user_id, YEAR(post_date) action_year, MONTH(post_date) action_month FROM content
  UNION
  SELECT DISTINCT user_id, YEAR(comment_date) action_year, MONTH(comment_date) action_date FROM comment
  ) T
GROUP BY
  T.action_year,
  T.action_month
ORDER BY
  T.action_year ASC,
  T.action_month ASC

Answer 2

这未经过测试。

select count(table1.user_id), table1.user_id
from table1 table2 
where table1.user_id = table2.user_id
And table2.comment_date like 'may'

Answer 3

试试这个

select TO_CHAR(order_dt,'MON-YYYY'), count(distinct User_ID ) cnt from [orders] 
where User_ID  in 
(select User_ID from
 (select a.User_ID from  [orders] a,
(select a.User_ID,count (a.order_dt) from [orders] a 
where a.order_dt > (select max(b.order_dt)-365 from [orders] b where a.User_ID=b.User_ID)
group by a.User_ID
having count(order_dt)>1) b
where a.User_ID=b.User_ID) a
)
group by TO_CHAR(order_dt,'MON-YYYY');

mysql - 如何获得每月发布或评论的唯一活跃用户数？

3 个答案: