我有一个Ruby脚本可以完成一些长期工作。它只是命令行,我想表明脚本仍在运行而不是停止。我曾经喜欢过去所谓的“旋转光标”,我设法在Windows下用Ruby重现它。
问题:这在其他操作系统中有效吗?如果没有,是否有与操作系统无关的方法来实现这一目标?
请不要使用IRB解决方案。
10.times {
print "/"
sleep(0.1)
print "\b"
print "-"
sleep(0.1)
print "\b"
print "\\"
sleep(0.1)
print "\b"
print "|"
sleep(0.1)
print "\b"
}
答案 0 :(得分:35)
是的,这适用于Windows,OS X和Linux。改善Niklas'建议,你可以这样更通用:
def show_wait_cursor(seconds,fps=10)
chars = %w[| / - \\]
delay = 1.0/fps
(seconds*fps).round.times{ |i|
print chars[i % chars.length]
sleep delay
print "\b"
}
end
show_wait_cursor(3)
如果您不知道该过程需要多长时间,您可以在另一个帖子中执行此操作:
def show_wait_spinner(fps=10)
chars = %w[| / - \\]
delay = 1.0/fps
iter = 0
spinner = Thread.new do
while iter do # Keep spinning until told otherwise
print chars[(iter+=1) % chars.length]
sleep delay
print "\b"
end
end
yield.tap{ # After yielding to the block, save the return value
iter = false # Tell the thread to exit, cleaning up after itself…
spinner.join # …and wait for it to do so.
} # Use the block's return value as the method's
end
print "Doing something tricky..."
show_wait_spinner{
sleep rand(4)+2 # Simulate a task taking an unknown amount of time
}
puts "Done!"
这个输出:
Doing something tricky...|
Doing something tricky.../
Doing something tricky...-
Doing something tricky...\
(et cetera)
Doing something tricky...done!
答案 1 :(得分:4)
# First define your chars
pinwheel = %w{| / - \\}
# Rotate and print as often as needed to "spin"
def spin_it
print "\b" + pinwheel.rotate!.first
end
来自彼得的编辑:这是一个工作版本
def spin_it(times)
pinwheel = %w{| / - \\}
times.times do
print "\b" + pinwheel.rotate!.first
sleep(0.1)
end
end
spin_it 10
答案 2 :(得分:3)
我写了一个gem spin_to_win,它在显示一个微调器的同时产生一个块。例如:
SpinToWin.with_spinner('Zzzz') do |spinner|
spinner.banner('sleepy')
sleep 1
end
Zzzz \ [sleepy]
它还可以跟踪未完成的工作与完成的工作:
SpinToWin.with_spinner('Zzzz') do |spinner|
spinner.increment_todo!(3)
spinner.banner('snore')
sleep 1
spinner.increment_done!
spinner.banner('dream')
sleep 1
spinner.increment_done!
spinner.banner('wake up!')
sleep 1
spinner.increment_done!
end
Zzzz \ 3 of 3 [wake up!]