我正在使用jQuery插件,它通过操纵div
的css将2.0 3.0转换为2星图像或3星图像。
jQuery代码是
<script type="text/javascript">
$(function () {
$('span.stars').stars();
});
$.fn.stars = function () {
return $(this).each(function () {
$(this).html($('<span />').width(Math.max(0, (Math.min(5, parseFloat($(this).html())))) * 16));
});
}
</script>
和css就是这个
span.stars, span.stars span
{
display: block;
background: url(../../Images/star.png) 0 -16px repeat-x;
width: 80px;
height: 16px;
}
span.stars span
{
background-position: 0 0;
}
但是现在我想在复选框列表中应用它,但我没有找到正确的方法。
我的复选框列表如下:
<asp:CheckBoxList ID="chbStars" runat="server" AutoPostBack="true" OnSelectedIndexChanged="chbStars_SelectedIndexChanged">
<asp:ListItem Text="1" Value="1.0"> </asp:ListItem>
<asp:ListItem Text="2" Value="2.0"> </asp:ListItem>
<asp:ListItem Text="3" Value="3.0"> </asp:ListItem>
<asp:ListItem Text="4" Value="4.0"> </asp:ListItem>
<asp:ListItem Text="5" Value="5.0"> </asp:ListItem>
</asp:CheckBoxList>
我通过像这样操纵css来尝试这个
#ctl00_ContentPlaceHolder1_chbStars label
{
background: url(../../Images/star.png) 0 -16px repeat-x;
width: 80px;
height: 16px;
}
#ctl00_ContentPlaceHolder1_chbStars span
{
background-position: 0 0;
}
但我没有找到改变jQuery的正确方法?
任何方向对我都有很大的帮助。
对于span,渲染的HTML是
<span style="width: 32px;"></span>
对于checkboxlist,呈现的HTML是
<table border="0" id="ctl00_ContentPlaceHolder1_chbStars">
<tbody><tr>
<td><input type="checkbox" onclick="javascript:setTimeout('__doPostBack(\'ctl00$ContentPlaceHolder1$chbStars$0\',\'\')', 0)" name="ctl00$ContentPlaceHolder1$chbStars$0" id="ctl00_ContentPlaceHolder1_chbStars_0"><label for="ctl00_ContentPlaceHolder1_chbStars_0">1</label></td>
</tr><tr>
<td><input type="checkbox" onclick="javascript:setTimeout('__doPostBack(\'ctl00$ContentPlaceHolder1$chbStars$1\',\'\')', 0)" name="ctl00$ContentPlaceHolder1$chbStars$1" id="ctl00_ContentPlaceHolder1_chbStars_1"><label for="ctl00_ContentPlaceHolder1_chbStars_1">2</label></td>
</tr><tr>
<td><input type="checkbox" onclick="javascript:setTimeout('__doPostBack(\'ctl00$ContentPlaceHolder1$chbStars$2\',\'\')', 0)" name="ctl00$ContentPlaceHolder1$chbStars$2" id="ctl00_ContentPlaceHolder1_chbStars_2"><label for="ctl00_ContentPlaceHolder1_chbStars_2">3</label></td>
</tr><tr>
<td><input type="checkbox" onclick="javascript:setTimeout('__doPostBack(\'ctl00$ContentPlaceHolder1$chbStars$3\',\'\')', 0)" name="ctl00$ContentPlaceHolder1$chbStars$3" id="ctl00_ContentPlaceHolder1_chbStars_3"><label for="ctl00_ContentPlaceHolder1_chbStars_3">4</label></td>
</tr><tr>
<td><input type="checkbox" onclick="javascript:setTimeout('__doPostBack(\'ctl00$ContentPlaceHolder1$chbStars$4\',\'\')', 0)" name="ctl00$ContentPlaceHolder1$chbStars$4" id="ctl00_ContentPlaceHolder1_chbStars_4"><label for="ctl00_ContentPlaceHolder1_chbStars_4">5</label></td>
</tr>
</tbody></table>
答案 0 :(得分:0)
您必须将jQuery选择器更改为$('#ctl00_ContentPlaceHolder1_chbStars label').stars();
你必须调整.css,#ctl00_ContentPlaceHolder1_chbStars标签以跨越
我希望这会显示你的东西,通过复选框的选择需要编码..