我是JSON / Spring MVC的新手,我想尝试一个简单的例子来调用Spring MVC控制器的AJAX - 但我一直都会返回错误400 - 错误请求。
在浏览互联网之后,我发现这通常是由于没有设置适当的内容类型 - 但[我相信]我已经这样做了。
这是我的AJAX电话:
//validate the object
var urlString = "/ajax/add/";
$.ajax({
type:"POST",
url: urlString,
contentType: "application/json; charset=utf-8",
dataType: "json",
data: {value1: 'apples', value2 : 'oranges'},
success: function(result){
alert("success");
},
error: function(jqXHR, textStatus, errorThrown){
alert("error:" + textStatus + " exception:" + errorThrown);
}
}) ;
我的控制员:
@Controller
itpublic class AddController {
private static Logger m_log = null;
@RequestMapping(value = "/ajax/add")
public String handle(@RequestBody String json){
DummyClass dummyRequest;
try {
ObjectMapper mapper = new ObjectMapper();
dummyRequest = mapper.readValue(json, DummyClass.class);
m_log.info("Value1: " + dummyRequest.getValue1());
m_log.info("Value2: " + dummyRequest.getValue2());
} catch (Exception e) {
}
finally{
}
return "called";
}
任何人都可以帮助我吗?
修改的
以下是我用来配置Spring的上下文:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.project.do" />
<!--<mvc:annotation-driven/> -->
<bean class="com.project.do.interceptors.handler.mapping.HandlerInterceptorAnnotationAwareHandlerMapping "/>
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />
<bean class="com.project.do.viewresolver.ProjectViewResolver" >
<property name="tilesResolver" ref="tilesResolver" />
<property name="jspResolver" ref="jspResolver" />
</bean>
<bean id="tilesResolver" class ="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.tiles2.TilesView" />
<property name="order" value="2" />
</bean>
<bean id="jspResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
<property name="order" value="3" />
</bean>
<bean id ="tilesConfigurer" class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions" value="/WEB-INF/tiles/tiles.xml" />
<property name="preparerFactoryClass" value="org.springframework.web.servlet.view.tiles2.SpringBeanPreparerFactory"/>
</bean>
<mvc:resources mapping="/css/**" location="/css/" />
<mvc:resources mapping="/js/**" location="/js/" />
<mvc:resources mapping="/images/**" location="/images/" />
<mvc:resources mapping="/javascript/**" location="/javascript/" />
<mvc:resources mapping="/scripts/**" location="/scripts/" />
<mvc:resources mapping="/styles/**" location="/styles/" />
<mvc:resources mapping="/help/**" location="/help/" />
<!-- <mvc:view-controller path="/" view-name="welcome"/> -->
我应该注意到我在com.project.do.working包中有一个带Ajax的工作控制器,但是带有Ajax和JSON的非工作控制器在同一个包com.project.do.not.working
答案 0 :(得分:1)
我认为您的请求映射没有将RequestMethod作为POST。我想默认情况下它会获取一个get请求,但你的AJAX是一个POST请求。尝试更改如下
@RequestMapping(value = "/ajax/add", method = RequestMethod.POST)
public String handle(@RequestBody String json){
}
答案 1 :(得分:0)
@Controller
@RequestMapping("/employee/add.htm")
public class EmployeeController {
@RequestMapping(method = RequestMethod.POST)
public @ResponseBody
Employee add(HttpServletRequest request, HttpServletResponse response)
throws Exception {
}
}