Question

我只需编写以下愚蠢的类来避免疯狂：

import java.io.OutputStream;

import org.w3c.dom.Document;
import org.w3c.dom.bootstrap.DOMImplementationRegistry;
import org.w3c.dom.ls.DOMImplementationLS;
import org.w3c.dom.ls.LSOutput;
import org.w3c.dom.ls.LSSerializer;

public final class XMLSerializer {
    public static final void writeDocument(Document input, OutputStream output) {
        try {
            DOMImplementationLS ls = 
                (DOMImplementationLS) DOMImplementationRegistry
                .newInstance().getDOMImplementation("LS");
            LSSerializer ser = ls.createLSSerializer();
            LSOutput out = ls.createLSOutput();
            out.setByteStream(output);
            ser.write(input, out);
        } catch (Exception e) { // DIAF Java
            throw new RuntimeException(e);
        }
    }
}

这种便捷方法是否已经存在于Java或公共库中？这看起来有点啰嗦，甚至是所有例外都在“捕获（例外e）”下崩溃的版本。

Answer 1

试试这个：

DOMSource domSource = new DOMSource(input);
StreamResult resultStream = new StreamResult(output);
TransformerFactory transformFactory = TransformerFactory.newInstance();
try {
    serializer.transform(domSource, resultStream);
} catch (javax.xml.transform.TransformerException e) {
}

Answer 2

试试dom4j。它是一个优秀的XML库。

Java中的XML输出 - DOMImplementationLS是什么？

2 个答案: