Question

我有以下php将图像上传到服务器，并在数据库中插入名称：

<?php

//Uploading File to server php folder//
$uploaddir = ''; //Uploading to same directory as PHP file

$file = basename($_FILES['userfile']['name']);

$uploadFile = $file;

$randomNumber = rand(0000, 99999); 

$newName = $uploaddir . $randomNumber . $uploadFile;

if (is_uploaded_file($_FILES['userfile']['tmp_name'])) {
echo "Temp file uploaded. \r\n";
 } 

else {
echo "Temp file not uploaded. \r\n";
}


if (move_uploaded_file($_FILES['userfile']['tmp_name'], $newName)) {
$postsize = ini_get('post_max_size'); 
$canupload = ini_get('file_uploads');  
$tempdir = ini_get('upload_tmp_dir'); 
$maxsize = ini_get('upload_max_filesize');
echo "http://localhost/abc/images/{$newName}" . "\r\n" . $_FILES['userfile']['size'] .    "\r\n" . $_FILES['userfile']['type'] ;
}



//Making sql db connection to store image path in db table//

$host = "localhost";

$username = "root";
$password = "****";

$database = "userauth";

mysql_connect($host, $username);

mysql_select_db($database) or die("Unable to find database");

$image = $_GET["images"];

$qry = "INSERT INTO image VALUES ('','$newName')";

mysql_query($qry);

mysql_close();
    ?>

上面的代码可以轻松上传临时名称的文件：upload_image以随机编号前置到以下xampp文件夹路径：http://localhost/abc/images/

在db表中，我将图像名称修改为＆＃39; randomnumber＆＃39; upload_image.jpg。我需要的是我需要db表来显示图像名称以及完整路径http://localhost/abc/images/＆＃39; rand.number＆＃39; upload_image.jpg

我如何实现这一目标？

我尝试用＆＃34; http：// localhost / abc / images /＆＃34;替换uploaddir;并尝试将其添加到新文件名，但它返回以下警告：

<b>Warning</b>:  move_uploaded_file(http://localhost/abc/images/33760upload_image.jpg)   [<a href='function.move-uploaded-file'>function.move-uploaded-file</a>]: failed to open   stream: HTTP wrapper does not support writeable connections in    <b>/Applications/XAMPP/xamppfiles/htdocs/xampp/abc/images/imageupload.php</b> on line    <b>24</b><br />
<br />
<b>Warning</b>:  move_uploaded_file() [<a href='function.move-uploaded-file'>function.move-uploaded-file</a>]: Unable to move '/Applications/XAMPP/xamppfiles/temp/phpdlCc5N' to 'http://localhost/abc/images/33760upload_image.jpg' in <b>/Applications/XAMPP/xamppfiles/htdocs/xampp/abc/images/imageupload.php</b> on line   <b>24</b>
<br />

需要宝贵的指导。

PS：允许读取和写入权限表包含两个字段：ID和图像，ID设置为主要和自动增量

Answer 1

http://php.net/manual/en/reserved.variables.server.php

使用$_SERVER数组，您可以访问某些http请求详细信息，例如路径

您不应该尝试将上传的文件从/移动到像http这样的只读协议。而只是从php tmp目录中获取它。也不要在移动时启动这样的文件名，这会导致你的错误。

PHP：上传HTTP Path前面带有图像名称的图像？

1 个答案: