我有一个3des加密的十六进制字符串,我从服务器获得。当我用Java ECB / NoPadding解密它时,我得到了预期的值,但是当我尝试用PHP解密它时,我得到了不同的值。这是PHP代码:
<?php
$key = "428982f4658cfeb679bae2bf85ebcde9";
$input = "9CB39217A434F6339EF27C503B561342";
$encrypted_data = bin2hex(
mcrypt_ecb(MCRYPT_3DES, pack("H*", $key), pack("H*", $input), MCRYPT_DECRYPT)
);
?>
以及以main开头的部分java代码:
String input = "F414E86894D996F8658F9327C8EC786404192012174729";
String key = "05aa58f38a0883d1439750a2495d36ad";
byte2hex(doCryto("F414E86894D996F8658F9327C8EC7864", "05aa58f38a0883d1439750a2495d36ad", Cipher.DECRYPT_MODE));
public static byte[] doCryto(String data, String key, int CipherMode) throws Exception {
byte result[];
try {
byte data1[] = hex2byte(data);
Key key1 = formDESKey(key);
transformation = key1.getAlgorithm() + "/ECB/NoPadding";
Cipher c1 = Cipher.getInstance(transformation);
c1.init(CipherMode, key1);
result = c1.doFinal(data1);
} catch (Exception e) {
throw new Exception(e);
}
return result;
}
public static Key formDESKey(String key) throws Exception {
short len = (short) ((key.length() / 2) * 8);
return formDESKey(len, hex2byte(key));
}
public static Key formDESKey(short keyLength, byte clearKeyBytes[]) throws Exception {
Key key = null;
switch (keyLength) {
case 64: // '@'
key = new SecretKeySpec(clearKeyBytes, "DES");
break;
case 128:
clearKeyBytes = concat(clearKeyBytes, 0, 128/8, clearKeyBytes, 0, getBytesLength((short) 64));
// fall through
case 192:
key = new SecretKeySpec(clearKeyBytes, "DESede");
break;
}
if (key == null) {
throw new Exception("Unsupported DES key length: " + keyLength + " bits");
} else {
return key;
}
}
private static byte[] concat(byte array1[], int beginIndex1, int length1, byte array2[], int beginIndex2, int length2) {
byte concatArray[] = new byte[length1 + length2];
System.arraycopy(array1, beginIndex1, concatArray, 0, length1);
System.arraycopy(array2, beginIndex2, concatArray, length1, length2);
return concatArray;
}
Java结果:31303031464646464646464646464646
PHP结果为:411C689D687F2F118EA05BF234F4E582
我不知道为什么PHP会获得不同的价值。任何帮助将不胜感激 感谢。