通过Field JQuery / JS压缩Json Objects

Question

我有以下JSON：

[{"state":"MN","value":10},{"state":"MN","value":10},{"state":"MN","value":10},{"state":"NY","value":8},{"state":"NY","value":8},{"state":"NY","value":8}]

是否有JQuery / JS中的命令或任何其他HTML兼容语言允许我将上述JSON转换为以下内容：

[{"state":"MN","value":[10,10,10]},{"state":"NY","value":[8,8,8]}]

谢谢！

Answer 1

下面的循环将为您提供所需的输出

DEMO

var data = [{"state":"MN","value":10},{"state":"MN","value":10},{"state":"MN","value":10},{"state":"NY","value":8},{"state":"NY","value":8},{"state":"NY","value":8}];

var tmp = {};
var t;
$.each (data, function (i, val) {
   if (tmp.hasOwnProperty(val.state)) {
      t = tmp[val.state];
      t.push(val.value);
   } else {
      tmp[val.state] = [val.value];
   }   
});

var output = [];
for (i in tmp) {
    output.push({'state': i, 'value': tmp[i]});   
}

<强>证明：

Answer 2

你可以使用：

var input=[{"state":"MN","value":10},{"state":"MN","value":10},{"state":"MN","value":10},{"state":"NY","value":8},{"state":"NY","value":8},{"state":"NY","value":8}]

var tmp={}, output=[];
while(o=input.pop()) (tmp[o.state] || (tmp[o.state]=[])).push(o.value); //you could even stop here if it is enough for you
for(k in tmp) output.push({state:k,value:tmp[k]});