我有下一张桌子
create table use_flags3 (
id INTEGER,
flag_name VARCHAR NOT NULL,
flag_description VARCHAR NOT NULL,
flag_type_id INTEGER NOT NULL,
package_id INTEGER,
FOREIGN KEY (flag_type_id) REFERENCES use_flags_types(id),
FOREIGN KEY (package_id) REFERENCES packages(id),
PRIMARY KEY (id)
);
当flag_type_id等于1时,我需要flag_name
列为唯一 。我尝试使用下一个约束来实现此目的
CONSTRAINT idx1_chk CHECK (
flag_type_id in (select id from use_flags_types where flag_type="local") or
flag_type_id in (select id from use_flags_types where flag_type="expand") or
flag_type_id in (select id from use_flags_types where flag_type="expand_hidden") or
(
flag_type_id in (select id from use_flags_types where flag_type="global") and
flag_name not in (select flag_name from use_flags)
)
)
sqlite说'CHECK约束中禁止'子查询'。我可以替换
flag_type_id in (select id from use_flags_types where flag_type="local")
带
flag_type_id = ${ID_HERE} -- id from `select id from use_flags_types where flag_type="local"`
但我不能对约束的最后一部分的第二个子部分做同样的技巧
flag_name not in (select flag_name from use_flags)
有没有机会在一张桌子里做我原本想要的东西(我真的不喜欢将这些数据分成2(+)个表格)?
//希望描述很清楚
答案 0 :(得分:3)
如果您有复杂的约束,则应使用触发器:
http://sqlfiddle.com/#!7/2094c
CREATE TABLE use_flags3 (
id INTEGER,
flag_name VARCHAR NOT NULL,
flag_description VARCHAR NOT NULL,
flag_type_id INTEGER NOT NULL,
package_id INTEGER,
FOREIGN KEY (flag_type_id) REFERENCES use_flags_types(id),
FOREIGN KEY (package_id) REFERENCES packages(id),
PRIMARY KEY (id)
);
/* TRIGGER BEFORE UPDATE version omitted */
CREATE TRIGGER fake_unique
BEFORE INSERT ON use_flags3
FOR EACH ROW
WHEN (
EXISTS (SELECT NULL
FROM use_flags_types
WHERE flag_type IN( "local", "expand", "expand_hidden")
AND flag_type_id = id
)
OR (
EXISTS (SELECT NULL
FROM use_flags_types
WHERE flag_type="global"
AND flag_type_id = id)
AND flag_name NOT IN (SELECT flag_name FROM use_flags)
)
)
BEGIN
SELECT RAISE( ABORT, 'duplicate rows' );
END;