Question

当需要固定块时，我有点困惑。我有一个例子，它给了我一个矛盾的场景：

enum RoomType { Economy, Buisness, Executive, Deluxe };

struct HotelRoom
{
    public int Number;
    public bool Taken;
    public RoomType Category;

    public void Print()
    {
        String status = Taken ? "Occupied" : "available";
        Console.WriteLine("Room {0} is of {1} class and is currently {2}", Number, Category, status);
    }
}

我创建了一个函数，它将指向HotelRoom

private unsafe static void Reserve(HotelRoom* room)
{
    if (room->Taken)
        Console.WriteLine("Cannot reserve room {0}", room->Number);
    else
        room->Taken = true;
}

在主要方法中，我有以下内容：

unsafe static void Main(string[] args)
{
    HotelRoom[] myfloor = new HotelRoom[4];
    for (int i = 0; i < myfloor.Length; i++)
    {
        myfloor[i].Number = 501 + i;
        myfloor[i].Taken = false;
        myfloor[i].Category = (RoomType)i;
    }
    HotelRoom Room =  myfloor[1];
    Reserve(&Room);   //I am able to do this without fixed block.
    //Reserve(&myfloor[1]);  //Not able to do this so have to use fixed block below. 

    fixed (HotelRoom* pRoom = &myfloor[1])
    {
        Reserve(pRoom);
    }

    myfloor[1].Print();
    Room.Print();
}

我的困惑是我可以Reserve(&Room)而不是Reserve(&myfloor[1])。我认为他们正在做同样的事情 - 将HotelRoom结构的记忆地址传递给Reserve函数。为什么我需要fixed来执行此操作？