我有2个像这样的结构表：
People
----------
>ID, Name, Surname
Projects
----------
>ID, Assistant#1, Assistant#2, Assistant#3, Assistant#4,
> Assistant#5, Assistant#6, Assistant#7, Assistant#8, Assistant#9,
> Assistant#10, lot of other columns..... (every assistant column
> contains an integer, the people ID)
现在，我想查询我的数据库并从Project表中获取一行（让我们假设ID = 3的行）包含项目表的所有列，特别是每个助手都用它的正确名称和姓氏替换。 我已经设法做了这个（有很多连接），但是凭借我的小经验，我的代码看起来非常笨重，而且我确信有更好的方法可以做到这一点。
提前致谢。
答案 0 :(得分：6)
SELECT p.Name, p.Surname
FROM People p
CROSS JOIN Project j ON (p.PeopleID = j.Assistant1 OR
p.PeopleID = j.Assistant2 OR
p.PeopleID = j.Assistant3 OR
.. etc)
AND j.ProjectID = 3
你的表现会很糟糕，但这是你为拥有一个设计糟糕的数据库而付出的代价。更好的解决方案是通过分解来映射项目和人员：
CREATE TABLE proj_people
People_ID INT
Project_ID INT
答案 1 :(得分：4)
我的结构不清楚。我建议你为项目创造一个离合器。
表：
Peoples
people_id，people_name，people_surname
Projects
project_id，project_name
Clutch
project_id，people_id
答案 2 :(得分：0)
未经测试：）
Select * from project pr
left join people pe1 on pe1.peopleid = pr.astint1
left join people pe2 on pe2.peopleid = pr.astint2
left join people pe3 on pe3.peopleid = pr.astint3
left join people pe4 on pe4.peopleid = pr.astint4
left join people pe5 on pe5.peopleid = pr.astint5
left join people pe6 on pe6.peopleid = pr.astint6
left join people pe7 on pe7.peopleid = pr.astint7
left join people pe8 on pe8.peopleid = pr.astint8
left join people pe9 on pe9.peopleid = pr.astint9
left join people pe10 on pe10.peopleid = pr.astint10
where pr.projectid = 3
答案 3 :(得分：0)
也许更清洁的设计是：
人员表：
People ID, Name, Surname
ProjectAssistants表：
Project ID, Assistant Person ID
项目表：
Project ID, lots of other columns (but no Assistant columns)
然后，SQL就变成了：
SELECT pr.*, p.*
FROM Projects pr
JOIN ProjectAssistants p_a ON pr.ProjectID = p_a ProjectID
JOIN People p ON p_a.AssistantPersonID = p.PeopleID
WHERE ProjectID = X
答案 4 :(得分：0)
您的问题是您正在尝试在数据库级别解决数据呈现问题，这很少是一个好主意。你应该有一个只包含projectid和assistantid的表，将两列的组合作为表的主键。这将允许您只将此表连接到助手表和项目表一次，并获得所需的所有结果。这样做的好处是，您可以在将来支持更多项目助理，而无需更改查询以添加更多联接。
总之，你应该有3个表：
Project
Assistant
ProjectAssistant (projectid,assistantid)
答案 5 :(得分：0)
您要重组表格。我讨厌多次查看具有多列的表格。如果重组为3个表：
人
PeopleID | Name | Surname
项目
ProjectID | ...other columns except Assistant
Project_Person
ProjectID | PersonID
这样，您可以将多个助手分配到同一个项目，而无需多个助手列。然后你可以使用这样的东西来获得所需的结果：
SELECT proj.ProjectID, pers.Name, pers.Surname
FROM Person pers
INNER JOIN Project_Person pp ON pp.PersonID = pers.PersonID
INNER JOIN Project proj ON proj.ProjectID = pp.ProjectID
这不会返回单行，但这不是SQL的工作方式。
答案 6 :(得分：0)
如果您不想/不能更改表结构，那么可能使用用户定义的函数？
CREATE FUNCTION GET_ASS_NAME (n1 ASS_NO)
RETURNS VARCHAR(50)
DETERMINISTIC
BEGIN
DECLARE fullname VARCHAR(50);
SELECT fullname = CONCAT(NAME, ' ', SURNAME) FROM PEOPLE WHERE ID = n1;
RETURN fullname;
END|
然后
select GET_ASS_NAME(1), GET_ASS_NAME(2), GET_ASS_NAME(3), ...
from PROJECTS
where ID = 3
答案 7 :(得分：0)
因为您将一些（可能的）助手设置为10，这就要求您必须编写代码来容纳这10名助手。这可以通过以下几种方式完成:(尚未测试）
select * from projects proj
left join people p1 on proj.assistant1 = p1.peopleid
left join people p2 on proj.assistant2 = p2.peopleid
left join people p3 on proj.assistant3 = p3.peopleid
left join people p4 on proj.assistant4 = p4.peopleid
left join people p5 on proj.assistant5 = p5.peopleid
left join people p6 on proj.assistant6 = p6.peopleid
left join people p7 on proj.assistant7 = p7.peopleid
left join people p8 on proj.assistant8 = p8.peopleid
left join people p9 on proj.assistant9 = p9.peopleid
left join people p10 on proj.assistant10 = p10.peopleid
否则你可以用
做一些诡计select proj.projectID,
(select * from people where peopleID = proj.assistant1),
(select * from people where peopleID = proj.assistant2),
(select * from people where peopleID = proj.assistant3),
(select * from people where peopleID = proj.assistant4),
(select * from people where peopleID = proj.assistant5),
(select * from people where peopleID = proj.assistant6),
(select * from people where peopleID = proj.assistant7),
(select * from people where peopleID = proj.assistant8),
(select * from people where peopleID = proj.assistant9),
(select * from people where peopleID = proj.assistant10)
from projects proj
如果可能，最好重新构建数据表，并将单个助手映射到单个projectID：
PeopleID, Name, Surname
ProjectID, PeopleID
因此，您只能进行一次内连接，并为每位助手返回一行：
select * from projects proj
inner join people p
on p.peopleID = proj.peopleid
where proj.projectID = PROJECTID