Question

参考标题。我有一个我编码的数组： -

$query = "SELECT * FROM server";
$result = mysql_query($query);
$dServer = array();

while($row = mysql_fetch_assoc($result)) {
    $dServer[] = $row['model'];
}

现在，如何将 $ dServer 数组传递给Javascript数组？

例如，这个数组：

var a = new Array();

Answer 1

$query = "SELECT * FROM server";
$result = mysql_query($query);
$dServer = array();

while($row = mysql_fetch_assoc($result)){
    $dServer[] = $row['model'];
}    

?>
<script type="text/javascript">
    var a = <?php echo json_encode($dServer); ?>;
</script>

Answer 2

将其编码为json对象。

<?
    $arr = array('entry' => 'content');
?>

<script>
var data = <?=json_encode($arr);?>;
alert(data['entry']);
</script>

Answer 3

尝试使用ajax请求和json_encode。

第二个变种

<?php
$query = "SELECT * FROM server";
$result = mysql_query($query);
$dServer = array();

     while($row = mysql_fetch_assoc($result))
      {
              $dServer[] = $row['model'];
      }    
?>
var a = <?php echo json_encode($dServer);?>;

Answer 4

除了提到的ajax / json方法，您还可以直接打印出值：

<?php
  $query = "SELECT * FROM server";
  $result = mysql_query($query);
?>

<script type="text/javascript">
  var a = new Array();

<?php
  while($row = mysql_fetch_assoc($result)){
    echo "a['model'] = " . $row['model'] . ";"; 
    echo "a['nextField'] = " . $row['nextField'] . ";"; 
  }
?>
</script>

将PHP数组传递给Javascript数组

4 个答案: