在下面的程序中,我试图将三角形旋转45度反向旋转。多边形确实旋转到某个角度并转换到其他位置。请告诉我如何解决这个问题。
#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>
int main(void)
{
int poly[8], rpoly[8],angle;
int gd = DETECT, gm;
initgraph(&gd,&gm,"C:\\TC\\BGI");
printf("\n Enter co-ordinates for Triangle : \n\n");
printf("Vertex 1 (x,y) : ");
scanf("%d %d", &poly[0], &poly[1]);
printf("Vertex 2 (x,y) : ");
scanf("%d %d", &poly[2], &poly[3]);
printf("Vertex 3 (x,y) : ");
scanf("%d %d", &poly[4], &poly[5]);
poly[6] = poly[0];
poly[7] = poly[1];
setcolor(2);
drawpoly(4,poly);
angle = 45;
rpoly[0] = poly[0]*cos(angle) - poly[1]*sin(angle);
rpoly[1] = poly[0]*sin(angle) + poly[1]*cos(angle);
rpoly[2] = poly[2]*cos(angle) - poly[3]*sin(angle);
rpoly[3] = poly[2]*sin(angle) + poly[3]*cos(angle);
rpoly[4] = poly[4]*cos(angle) - poly[5]*sin(angle);
rpoly[5] = poly[4]*sin(angle) + poly[5]*cos(angle);
rpoly[6] = rpoly[0];
rpoly[7] = rpoly[1];
setcolor(4);
drawpoly(4,rpoly);
getch();
closegraph();
return 0;
}
输出:
编辑1:
在输出中,红色三角形(即旋转后的三角形)看起来比原始三角形大。
新代码
#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>
int main(void)
{
int poly[8], rpoly[8], angle, centroid_x, centroid_y,i;
int gd = DETECT, gm;
initgraph(&gd,&gm,"C:\\TC\\BGI");
printf("\n Enter co-ordinates for Triangle : \n\n");
printf("Vertex 1 (x,y) : ");
scanf("%d %d", &poly[0], &poly[1]);
printf("Vertex 2 (x,y) : ");
scanf("%d %d", &poly[2], &poly[3]);
printf("Vertex 3 (x,y) : ");
scanf("%d %d", &poly[4], &poly[5]);
poly[6] = poly[0];
poly[7] = poly[1];
setcolor(2);
drawpoly(4,poly);
angle = 45 * 2 * 3.14 / 360;
centroid_x = (poly[0] + poly[2] + poly[4]) / 3;
centroid_y = (poly[1] + poly[3] + poly[5]) / 3;
rpoly[0] = (poly[0] - centroid_x) * cos(angle) - (poly[1] - centroid_y) * sin(angle) + centroid_x;
rpoly[1] = (poly[0] - centroid_x) * sin(angle) - (poly[1] - centroid_y) * cos(angle) + centroid_y;
rpoly[2] = (poly[2] - centroid_x) * cos(angle) - (poly[3] - centroid_y) * sin(angle) + centroid_x;
rpoly[3] = (poly[2] - centroid_x) * sin(angle) - (poly[3] - centroid_y) * cos(angle) + centroid_y;
rpoly[4] = (poly[4] - centroid_x) * cos(angle) - (poly[5] - centroid_y) * sin(angle) + centroid_x;
rpoly[5] = (poly[4] - centroid_x) * sin(angle) - (poly[5] - centroid_y) * cos(angle) + centroid_y;
rpoly[6] = rpoly[0];
rpoly[7] = rpoly[1];
setcolor(4);
drawpoly(4,rpoly);
for(i=0;i<7;i++)
{printf("\n %d", &rpoly[i]);}
getch();
closegraph();
return 0;
}
输出:
编辑2:
更正Y后的代码 - 术语:
#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>
int main(void)
{
int poly[8], rpoly[8], angle, centroid_x, centroid_y,i;
int gd = DETECT, gm;
initgraph(&gd,&gm,"C:\\TC\\BGI");
printf("\n Enter co-ordinates for Triangle : \n\n");
printf("Vertex 1 (x,y) : ");
scanf("%d %d", &poly[0], &poly[1]);
printf("Vertex 2 (x,y) : ");
scanf("%d %d", &poly[2], &poly[3]);
printf("Vertex 3 (x,y) : ");
scanf("%d %d", &poly[4], &poly[5]);
poly[6] = poly[0];
poly[7] = poly[1];
setcolor(2);
drawpoly(4,poly);
angle = 45 * 2 * 3.14 / 360;
centroid_x = (poly[0] + poly[2] + poly[4]) / 3;
centroid_y = (poly[1] + poly[3] + poly[5]) / 3;
rpoly[0] = (poly[0] - centroid_x) * cos(angle) - (poly[1] - centroid_y) * sin(angle) + centroid_x;
rpoly[1] = (poly[0] - centroid_x) * sin(angle) + (poly[1] - centroid_y) * cos(angle) + centroid_y;
rpoly[2] = (poly[2] - centroid_x) * cos(angle) - (poly[3] - centroid_y) * sin(angle) + centroid_x;
rpoly[3] = (poly[2] - centroid_x) * sin(angle) + (poly[3] - centroid_y) * cos(angle) + centroid_y;
rpoly[4] = (poly[4] - centroid_x) * cos(angle) - (poly[5] - centroid_y) * sin(angle) + centroid_x;
rpoly[5] = (poly[4] - centroid_x) * sin(angle) + (poly[5] - centroid_y) * cos(angle) + centroid_y;
rpoly[6] = rpoly[0];
rpoly[7] = rpoly[1];
setcolor(4);
drawpoly(4,rpoly);
// for(i=0;i<8;i++)
// {printf("\n %d", &rpoly[i]);}
getch();
closegraph();
return 0;
}
输出:
答案 0 :(得分:5)
两个问题:sin
和cos
在弧度中接受参数,而不是度数;你可能想要围绕它的中心旋转多边形,而不是关于(0,0)。
要解决第一个问题,请更改:
angle = 45;
为:
angle = 45.0 * 2.0 * M_PI / 360.0;
要解决第二个问题,首先需要计算多边形的质心,然后对顶点相对于质心的坐标进行平移。
答案 1 :(得分:4)
rpoly[0] = (poly[0] - centroid_x) * cos(angle) - (poly[1] - centroid_y) * sin(angle) + centroid_x;
rpoly[1] = (poly[0] - centroid_x) * sin(angle) + (poly[1] - centroid_y) * cos(angle) + centroid_y;
在rpoly [0]改变后计算rpoly [1]。
试试这个;
float newX = .......;
rpoly[0] = newX;
float newY = .......;
rpoly[1] = newY;