Question

我有以下表格：

父

ID
------
a
b
c

子

f_ID    ID
------------
a        1
a        2
a        3
b        1
b        2
c        1

我想：

当我[1,2,3]
当我[1,2]
当我[1]

问题是如果我使用

SELECT *    
FROM Father AS F    
INNER JOIN Child AS C    
ON C.f_ID = F.ID    
WHERE C.ID IN ( '1' )

这将给我父亲：1,2,3

请帮忙，我是SQL的新手

Answer 1

试试这样。我只是添加了一个＆＃34;并且不存在＆＃34;在你的Where子句的末尾。

SELECT * Father AS F
INNER JOIN Child AS C
    ON C.f_ID = F.ID
WHERE C.ID IN ( '1' )
AND NOT EXISTS (
    SELECT * FROM Child
    WHERE Child.ID NOT IN ('1')
    AND F.ID = Child.f_ID
)

作为替代方法，您可以自行连接并选择空行。

SELECT * Father AS F
INNER JOIN Child AS C
    ON C.f_ID = F.ID AND C.ID IN ( '1' )
LEFT OUTER JOIN
    (SELECT f_ID FROM Child WHERE ID NOT IN ('1')) a
    ON C.f_ID = a.f_ID
WHERE a.f_ID IS NULL

Answer 2

为了能够匹配整个序列，您需要计算匹配并将其与给定序列的计数进行比较：

select f.f_id
  from father f
 inner join child c
    on f.f_id = c.f_id
 -- exact sequence given
 where c.f_id in (1, 2, 3)
group by f_id
-- compare number of children to number of elements in parameter sequence
having count (distinct c.c_id) = 3

SQL - 获取＆＃34;确切＆＃34;父亲与孩子们比赛

父

子

2 个答案: