Question

在我的程序中，当我退出ASM代码部分并返回到C ++代码时，我在project00.exe中的0x93b3237d处获得Unhandled异常：0xC0000005：访问冲突。在Crtexe.c中，行mainret = main（argc，argv，envp）;并且在0C添加到ESP时的反汇编中。我认为问题可能是主函数的返回地址在返回之前被破坏并导致它失败。程序找到两组的交集和并集。使用VS10并且没有想法。


    include "iostream.h"//modify line to show up in code block

    using namespace std;

    typedef int DWORD;      //4 btye double word
    typedef char BYTE;      //1 byte 
    typedef short WORD;     //2 byte double word

    int main(){ 

    int i =0;
    BYTE str0[50] = "1qaz2wsx3edc4rfv5tgb6yhn7ujm8ik,9ol.0p;/-[?]F!Q"; 
    BYTE str1[50] ="QAZ@WSX#EDC$RFV%TGB^YHN&UJM*IK)P:?_{?}|1`"; 
    DWORD length0 ; 
    DWORD length1 ;
    BYTE IntersectArray[50]; 
    BYTE result [100] ;

    __asm{
    p:
    pusha
    lea eax, str0
    call COUNT 
    mov length0,ecx
    lea eax, str1
    call COUNT 
    mov length1,ecx
    call INTERSECTION
    call JoinSet
    xor eax,eax
    popa
    ret




    COUNT: 
    mov ecx,0;
    Q: mov dl, [eax]
    cmp dl,0h
    JE cEND
    inc eax
    inc ecx
    jmp Q
    cEnd: ret


    INTERSECTION:
        lea edx, str0
        mov ebx, length0
        lea esi, IntersectArray
        first: mov al, [edx]
        mov ecx, length1
        lea edi, str1
        repne SCASB
        cmp ecx,0
        JNZ INTER
    Back:   inc edx
        cmp ebx,0
        JZ EXITSTUFF
        dec ebx
        jmp first

    INTER: mov [esi] , al
       inc esi
       jmp Back

    EXITSTUFF:
        mov [esi], 0
        ret

    JoinSet :
        lea edi, result
        lea esi, str0
        mov ecx, length0
        REP MOVSB   



            lea edx, str1
        mov ebx, length1
        lea esi, result + [ebx]
        f: mov al, [edx]
        mov ecx, length0
        lea edi, str0
        repne SCASB
        cmp ecx,0
        JNZ B
         mov [esi] , al
           inc esi
    B:      inc edx
        cmp ebx,0
        JZ EXITSTU
        dec ebx
        jmp f

    EXITSTU:
        mov [esi], 0
        ret
    }

其余

    for(int i =0;i < 50;i++){
cout <<IntersectArray[i];}
cout << endl;
for (int i =0; i<100;i++)
cout <<result[i];
cout << endl;
system("pause");
return 0;
}

Answer 1

可能是一个愚蠢的评论，因为我从未做过任何x86程序集。但我认为asm是内联的？那么你的第一个'ret'实际上是从什么地方回来的？

project00.exe中0x93b3237d处的未处理异常：0xC0000005：访问冲突

1 个答案: