Question

感谢Joachim，但我无法进行编译，我认为这可能是我设置它的方式，所以我像你说的那样删除了for循环，并将函数合并到我的calculator.cpp文件中。所以当我编译程序时，会导致以下错误：

错误：`ParseNumberWord'未声明（首先使用此函数）

Calculator.h

    #ifndef CALCULATOR_H
    #define CALCULATOR_H

    class Calculator {
    //    float a, b;
    public:
        int add(int, int);
        int subtract(int, int);
        int multiply(int, int);
        int divide(int, int);
        int ParseNumberDigit();
        int ParseNumberWord();

    private:
        int n1;
        int n2;
    };

    #endif  /* CALCULATOR_H */

Calculator.cpp

#include "Calculator.h"


int Calculator::add(int n1, int n2) {
    return (n1 + n2);
}
int Calculator::subtract(int n1, int n2) {
    return (n1 - n2);
}
int Calculator::divide(int n1, int n2) {
    return (n1 / n2);
}
int Calculator::multiply(int n1, int n2) {
    return (n1 * n2);
}

int Calculator::ParseNumberDigit(std::string &number)
{
    int n = 0;
    for (int i = 9; i >= 0 && !number.empty(); i--) {
        if (number.find(Hund[i]) == 0) {
            n = i * 100;
            number = number.substr(Hund[i].length());
        }
        else if (number.find(Ten[i]) == 0) {
            n = i * 10;
            number = number.substr(Ten[i].length());
        }
        else if (number.find(Teen[i]) == 0) {
            n = i + 10;
            number = number.substr(Teen[i].length());
        }
        else if (number.find(One[i]) == 0) {
            n = i;
            number = number.substr(One[i].length());
        }

        if (n != 0)
            break;
    }

    return n;
}


int Calculator::ParseNumberWord(const std::string &word)
{
    std::string number = word;

    std::transform(number.begin(), number.end(), number.begin(), [](char c) { return std::tolower(c); });
    // If the above line doesn't work, you have to do it the old way:
    // for (int x = 0; x < number.length(); x++) { //input to lower case
    //     number[x] = std::tolower(number[x]);
    // }

    int n = 0;

    while (!number.empty()) {
        // Parse the next "digit"
        n += ParseNumberDigit(number);

        // The '_' is used to bind together digits
        if (number[0] == '_') {
            number = number.substr(1);
        }
    }

    return n;
}

main.cpp

#include <iostream>
#include <sstream>
#include "Calculator.h"
#include <algorithm>

using namespace std;
string Calualtor();

int main() {
    int length, result, OnesR, TensR;
    Calculator calc;
    string word1a, word2a;
    string word1, word2;
//    int result, OnesR, TensR;
    char arithmetic;



std::string One[10] = {"zero", "one", "two", "three", "four", "five", "six",
    "seven", "eight", "nine"};
std::string Teen[10] = {"", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen",
    "seventeen", "eighteen", "nineteen"};
std::string Ten[10] = {"", "ten", "twenty", "thirty", "forty", "fifty", "sixty",
    "seventy", "eighty", "ninety"};
std::string Hund[10] = {"", "one_hundred", "two_hundred", "three_hundred",
    "four_hundred", "five_hundred", "six_hundred", "seven_hundred", "eight_hundred",
    "nine_hundred"};



    while (cin >> word1 >> arithmetic >> word2) {


        int n1 = ParseNumberWord(word1);
        int n2 = ParseNumberWord(word2);

        switch (arithmetic) { //determines which arithmetic operation to perform
            case '+':
                result = calc.add(n1, n2);
                break;
            case '-':
                result = calc.subtract(n1, n2);
                break;
            case '*':
                result = calc.multiply(n1, n2);
                break;
            case '/':
                result = calc.divide(n1, n2);
                break;
            default:
                cout << 0 << endl;

        }

        // for the teen array
        if (result <= 19 && result >= 11 || result <= 119 && result > 111) {
            result = result % 10;
            cout << Teen[result] << endl;

        } else {
            for (int i = 1; i <= 2; i++) //Save individual digits to individual variables.
            {
                switch (i) {
                    case 1:
                        OnesR = result % 10;
                        result = result / 10;
                        break;
                    case 2:
                        TensR = result % 10;
                        result = result / 10;
                        break;
                }

            }

            if ((OnesR || TensR) < 0) { //To print a negative result

                OnesR = OnesR * -1;
                TensR = TensR * -1;
                cout << "negative " + Ten[TensR] << One[OnesR] << endl;
            } else {
                cout << Ten[TensR] << One[OnesR] << endl;
            }
        }


    }
}

Answer 1

首先是一个小提示：用于获取第一个和第二个数字的代码是相同的，将此代码转换为函数是个好主意。

至于你的问题，我看到其中有两个：第一个是无论你在循环中匹配什么“数字”字，你总是从One数组中删除，即这个行：

word1.erase(0, One[i].length());

应位于相应的if - 体内，并且也应使用正确的数组。

第二个问题是，在删除当前的数字后，实际上并没有检查到应该将数字绑定在一起的'_'字符。

修改

您需要做的第一件事是使数字字数组全局化。然后只需创建一个带字符串的函数，并返回一个数字：

#include <algorithm> std::string One[10] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}; std::string Teen[10] = {"", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}; std::string Ten[10] = {"", "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"}; std::string Hund[10] = {"", "one_hundred", "two_hundred", "three_hundred", "four_hundred", "five_hundred", "six_hundred", "seven_hundred", "eight_hundred", "nine_hundred"}; int ParseNumberDigit(std::string &number) { int n = 0; for (int i = 9; i >= 0 && !number.empty(); i--) { if (number.find(Hund[i]) == 0) { n = i * 100; number = number.substr(Hund[i].length()); } else if (number.find(Ten[i]) == 0) { n = i * 10; number = number.substr(Ten[i].length()); } else if (number.find(Teen[i]) == 0) { n = i + 10; number = number.substr(Teen[i].length()); } else if (number.find(One[i]) == 0) { n = i; number = number.substr(One[i].length()); } if (n != 0) break; } return n; } int ParseNumberWord(const std::string &word) { std::string number = word; std::transform(number.begin(), number.end(), number.begin(), [](char c) { return std::tolower(c); }); // If the above line doesn't work, you have to do it the old way: // for (int x = 0; x < number.length(); x++) { //input to lower case // number[x] = std::tolower(number[x]); // } int n = 0; while (!number.empty()) { // Parse the next "digit" n += ParseNumberDigit(number); // The '_' is used to bind together digits if (number[0] == '_') { number = number.substr(1); } } return n; }

在获得号码的main中，而不是for - 循环，只需使用：

int n1 = ParseNumberWord(word1); int n2 = ParseNumberWord(word2);

注意：上述功能经过测试可用。

c ++算术字数转换，请咨询

1 个答案: