我写了一个函数来包含给我一个介于两个DateTime
之间的小时列表。
但最后它看起来并不是很容易阅读,它让我想要对它进行单元测试,即使我正在进行的项目根本不进行单元测试。
所以我的问题是,是否有更清晰,更有效的方式来写这个?:
代码:
private List<DateTime> GetHoursForEvent(DateTime start, DateTime end)
{
var hours = new List<DateTime>();
DateTime startFloor = Convert.ToDateTime(start.ToString("MM/dd/yyyy HH:00:00"));
DateTime endFloor = Convert.ToDateTime(end.ToString("MM/dd/yyyy HH:00:00"));
for (double dblDate = startFloor.ToOADate();
dblDate <= endFloor.ToOADate();
dblDate += (1.0 / 24.0))
{
hours.Add(DateTime.FromOADate(dblDate));
}
return hours;
}
输入:
DateTime start = Convert.ToDateTime("2012-04-01 04:22:00");
DateTime end = Convert.ToDateTime("2012-04-02 00:05:00");
结果:
2012-04-01 04:00:00
2012-04-01 05:00:00
2012-04-01 06:00:00
2012-04-01 07:00:00
2012-04-01 08:00:00
2012-04-01 09:00:00
2012-04-01 10:00:00
2012-04-01 11:00:00
2012-04-01 12:00:00
2012-04-01 13:00:00
2012-04-01 14:00:00
2012-04-01 15:00:00
2012-04-01 16:00:00
2012-04-01 17:00:00
2012-04-01 18:00:00
2012-04-01 19:00:00
2012-04-01 20:00:00
2012-04-01 21:00:00
2012-04-01 22:00:00
2012-04-01 23:00:00
2012-04-02 00:00:00
我感觉我正在重新发明轮子。
答案 0 :(得分:9)
是的,这样的事情对你来说应该更好:
private List<DateTime> GetHoursForEvent(DateTime start, DateTime end)
{
var hours = new List<DateTime>();
var current = new DateTime(start.Year, start.Month, start.Day, start.Hour, 0, 0);
while(current <= end)
{
hours.Add(current);
current = current.AddHours(1);
}
return hours;
}
您甚至可能希望将其转换为流媒体方式,除非您需要返回List
的特定原因:
private IEnumerable<DateTime> GetHoursForEvent(DateTime start, DateTime end)
{
var current = new DateTime(start.Year, start.Month, start.Day, start.Hour, 0, 0);
while(current <= end)
{
yield return current;
current = current.AddHours(1);
}
}
答案 1 :(得分:1)
尝试使用此代码
private List<DateTime> GetHoursForEvent(DateTime start, DateTime end)
{
List<DateTime> hours = new List<DateTime>();
while (start < end)
{
hours.Add(start);
start = start.AddHours(1);
}
return hours;
}