如何在Win32 :: Console :: Input中捕获`shift` -`key`组合?

时间:2012-04-17 16:59:46

标签: perl winapi input console

如何使用此脚本捕获shift - some-key组合?
当我按下箭头键时,我得到了我期望的结果,但当我按shift - tab时,它不会返回KEY_BTAB值。

use warnings;
use 5.12.0;
use Win32::Console qw(STD_INPUT_HANDLE ENABLE_MOUSE_INPUT);
use constant {
    RIGHT_ALT_PRESSED  => 0x0001,
    LEFT_ALT_PRESSED   => 0x0002,
    RIGHT_CTRL_PRESSED => 0x0004,
    LEFT_CTRL_PRESSED  => 0x0008,
    SHIFT_PRESSED      => 0x0010,

    VK_LEFT     => 0x25,
    VK_UP       => 0x26,    
    VK_RIGHT    => 0x27,    
    VK_DOWN     => 0x28,    
    VK_TAB      => 0x09,    
};
use constant SHIFTED_MASK =>
    RIGHT_ALT_PRESSED |
    LEFT_ALT_PRESSED |
    RIGHT_CTRL_PRESSED |
    LEFT_CTRL_PRESSED |
    SHIFT_PRESSED;

my %d = (
    KEY_DOWN            => 258,
    KEY_UP              => 259,
    KEY_LEFT            => 260,
    KEY_RIGHT           => 261,
    KEY_BTAB            => 353,
);

my $con_in = Win32::Console->new(STD_INPUT_HANDLE);
$con_in->Mode(ENABLE_MOUSE_INPUT);

while ( 1 ) {
        my $key = getch();
        say "<$key>";
        last if $key == 113;
}

sub getch {
    my @event = $con_in->Input();
    my $event_type = shift( @event );
    if ( defined $event_type and $event_type == 1 ) { 
        my ( $key_down, $repeat_c, $vkcode, $vsccode, $char, $ctrl_ks ) = @event;
        if ( $char ) {
            return $char;
        }
        else {
            if ( $vkcode == VK_UP and ( $ctrl_ks & SHIFTED_MASK ) == 0 ) {
                return $d{KEY_UP};
            }
            elsif ( $vkcode == VK_DOWN and ( $ctrl_ks & SHIFTED_MASK ) == 0 ) {
                return $d{KEY_DOWN};
            }  
            elsif ( $vkcode == VK_RIGHT and ( $ctrl_ks & SHIFTED_MASK ) == 0 ) {
                return $d{KEY_RIGHT};
            }        
            elsif ( $vkcode == VK_LEFT and ( $ctrl_ks & SHIFTED_MASK ) == 0 ) {
                return $d{KEY_LEFT};
            } 
            elsif ( $vkcode == VK_TAB and $ctrl_ks == SHIFT_PRESSED ) {
                return $d{KEY_BTAB};    # <--
            }
            else {
                say "beep";
            }
        }
    }
}

当我按shifttab时输出:

&LT 1为卤素;
&LT; 9基
&LT; 9基

&LT 1为卤素;

以这种方式编辑getch例程

sub getch {
    my @event = $con_in->Input();
    my $event_type = shift( @event );
    if ( defined $event_type and $event_type == 1 ) { 
        my ( $key_down, $repeat_count, $virtual_keycode, $virtual_scancode, $char, $ctrl_key_state ) = @event;
        if ( $char ) {
            if ( $key_down ) {
                return $char for $repeat_count;
            }
        }
        else {
            if ( $virtual_keycode == VK_UP and ( $ctrl_key_state & SHIFTED_MASK ) == 0 ) {
                if ( $key_down ) {
                    return $d{KEY_UP} for $repeat_count;
                } 
            }
            elsif ( $virtual_keycode == VK_DOWN and ( $ctrl_key_state & SHIFTED_MASK ) == 0 ) {
                if ( $key_down ) {          
                    return $d{KEY_DOWN} for $repeat_count;
                }
            }  
            elsif ( $virtual_keycode == VK_RIGHT and ( $ctrl_key_state & SHIFTED_MASK ) == 0 ) {
                if ( $key_down ) {
                    return $d{KEY_RIGHT} for $repeat_count;
                }
            }        
            elsif ( $virtual_keycode == VK_LEFT and ( $ctrl_key_state & SHIFTED_MASK ) == 0 ) {
                if ( $key_down ) {
                    return $d{KEY_LEFT} for $repeat_count;
                }
            } 
            elsif ( $virtual_keycode == VK_TAB and ( $ctrl_key_state & SHIFTED_MASK ) == SHIFT_PRESSED ) {
                if ( $key_down ) {
                    return $d{KEY_BTAB} for $repeat_count;
                }
            }
            else {
                say "beep";
            }
        }
    }
}

我得到这个输出:

&LT 1为卤素;
&LT; 9基
&℃,GT;

&LT 1为卤素;

2 个答案:

答案 0 :(得分:3)

当我运行你的代码时,当我点击 Shift + Tab 时,$ctrl_ks的值为48(0x0030),当elsif ($vkcode==VK_TAB and ($ctrl_ks & SHIFT_PRESSED)==SHIFT_PRESSED) { return $d{KEY_BTAB}; 的值为32(0x0020) > Shift 已下达。我想你要做的检查是

{{1}}

答案 1 :(得分:1)

首先,$char设置为9,因此您永远不会进行检查。将if ($char)支票移至更合适的位置。


其次,你的检查是错误的。如果启用Caps Lock,则以下内容无效。

elsif ( $vkcode == VK_TAB and $ctrl_ks == SHIFT_PRESSED )

您应该只检查您感兴趣的旗帜。

elsif ($vkcode==VK_TAB and ( $ctrl_ks & SHIFTED_MASK ) == SHIFT_PRESSED)

最后,有时您只会收到一次多次通知的通知。这由$repeat_count发出信号。你忽略了这一点,所以你可能会忽略密钥。

您尝试在第二个代码段中处理$repeat_count,但却失败了。问题的一部分是你应该for $repeat_count从我的其他答案中复制for 1..$repeat_count,而另一个问题是,即使$repeat_count大于1,你也只返回一个值。< / p>


my @kbd_queue;
sub getch {
    my @event;
    if (@kbd_queue) {
       @event = ( 1, @{ pop @kbd_queue } );
    } else {
       @event = $con_in->Input();
    }

    my $event_type = shift( @event );
    if ( defined $event_type and $event_type == 1 ) { 
        my ( $key_down, $repeat_count, $virtual_keycode, $virtual_scancode, $char, $ctrl_key_state ) = @event;
        return -1 if !$key_down;

        if ( $virtual_keycode == VK_UP and ( $ctrl_key_state & SHIFTED_MASK ) == 0 ) {
            push @kbd_queue, \@event for 2..$repeat_count;
            return $d{KEY_UP};
        } 
        ...
        elsif ( $virtual_keycode == VK_TAB and ( $ctrl_key_state & SHIFTED_MASK ) == SHIFT_PRESSED ) {
            push @kbd_queue, \@event for 2..$repeat_count;
            return $d{KEY_BTAB};
        }
        elsif ( $char ) {
            push @kbd_queue, \@event for 2..$repeat_count;
            return $char;
        }
        else {
            say "beep";
        }
    }
}

你应该把它转换成桌面驱动的东西。