如何通过lambda表达式传递属性?

时间:2012-04-17 14:44:45

标签: c# lambda

我的项目中有一些单元测试,我们希望能够设置一些具有私有设置器的属性。目前我正在通过反射和这种扩展方法来做到这一点:

public static void SetPrivateProperty(this object sourceObject, string propertyName, object propertyValue)
{
    sourceObject.GetType().GetProperty(propertyName).SetValue(sourceObject, propertyValue, null);
}

假设我有一个像这样的TestObject:

public class TestObject
{
    public int TestProperty{ get; private set; }
}

然后我可以在我的单元测试中调用它,如下所示:

myTestObject.SetPrivateProperty("TestProperty", 1);

但是,我想在编译时验证属性名称,因此我希望能够在via表达式中传递属性,如下所示:

myTestObject.SetPrivateProperty(o => o.TestProperty, 1);

我该怎么做?

2 个答案:

答案 0 :(得分:9)

如果获取者是公开的,那么以下内容应该有效。它将为您提供如下所示的扩展方法:

var propertyName = myTestObject.NameOf(o => o.TestProperty);

它需要一个公共吸气剂。我希望,在某种程度上,像这样的反射功能已经融入了语言。

public static class Name
{
    public static string Of(LambdaExpression selector)
    {
        if (selector == null) throw new ArgumentNullException("selector");

        var mexp = selector.Body as MemberExpression;
        if (mexp == null)
        {
            var uexp = (selector.Body as UnaryExpression);
            if (uexp == null)
                throw new TargetException(
                    "Cannot determine the name of a member using an expression because the expression provided cannot be converted to a '" +
                    typeof(UnaryExpression).Name + "'."
                );
            mexp = uexp.Operand as MemberExpression;
        }

        if (mexp == null) throw new TargetException(
            "Cannot determine the name of a member using an expression because the expression provided cannot be converted to a '" +
            typeof(MemberExpression).Name + "'."
        );
        return mexp.Member.Name;
    }

    public static string Of<TSource>(Expression<Func<TSource, object>> selector)
    {
        return Of<TSource, object>(selector);
    }

    public static string Of<TSource, TResult>(Expression<Func<TSource, TResult>> selector)
    {
        return Of(selector as LambdaExpression);
    }
}

public static class NameExtensions
{
    public static string NameOf<TSource, TResult>(this TSource obj, Expression<Func<TSource, TResult>> selector)
    {
        return Name.Of(selector);
    }
}

答案 1 :(得分:4)

C#6.0新手:nameof(属性)