Question

保存图片的代码：

NSData *imageData=UIImagePNGRepresentation(animalImage);
        NSString *insertSQL=[NSString stringWithFormat:@"insert into AnimalsTable (name,propertyID,animalID,breed,mainBreed,dateofbirth,sex,notes,imageData) values(\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\",\"%@\")",nameString,propertyString,animalidString,breedString,mainBreedString,dateString,sexString,notesString,imageData];
    sqlite3_stmt *addStatement;
        NSLog(@"%@",appDelegate.sqlFile);
    const char *insert_stmt=[insertSQL UTF8String];
    if (sqlite3_open([appDelegate.sqlFile UTF8String],&database)==SQLITE_OK) {
        sqlite3_prepare_v2(database,insert_stmt,-1,&addStatement,NULL);

        if (sqlite3_step(addStatement)==SQLITE_DONE) {

            sqlite3_bind_blob(addStatement, 1, [imageData bytes], [imageData length], SQLITE_TRANSIENT);
            NSLog(@"Data saved");

        }
        else{
            //NSAssert1(0, @"Error while updating. '%s'", sqlite3_errmsg(database));

            NSLog(@"Some Error occured");
    }

    sqlite3_close(database);

用于检索图像：

NSString *select_sql=[NSString stringWithFormat:@"select name,animalID,imageData from AnimalsTable where mainBreed='%@' AND breed='%@'",mainString,subString];
        const char *sql = [select_sql UTF8String];
        sqlite3_stmt *selectstmt;
        if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) {

            while(sqlite3_step(selectstmt) == SQLITE_ROW) {

            NSString *animalName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 0)];
            NSString *animalid=[NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)];
            NSData *dataForCachedImage = [[NSData alloc] initWithBytes:sqlite3_column_blob(selectstmt, 2) length: sqlite3_column_bytes(selectstmt, 2)];           
            [animalNamesArray addObject:animalName];
            [animalIDArray addObject:animalid];
            [imageDataArray addObject:dataForCachedImage];

        }
    }
}
else
    sqlite3_close(database);

在UITableView CellForIndexPath中：

NSData *dataForCachedImage=[imageDataArray objectAtIndex:indexPath.row];
    UIImage *dataImage=[[UIImage alloc] init];
    dataImage=[UIImage imageWithData:dataForCachedImage];
    cell.imageView.image=dataImage;

当我调试代码时：

我得到NSData = 226381字节的字节和dataImage 0x0的字节。

请帮帮我。

Answer 1

您需要将值正确绑定到查询才能生效。在第一行上设置查询时，将插入数据描述而不是正确的数据。如果您要记录查询，您可能会看到<0FFAEC32 ... 23F0E8D1>之类的内容。然后，您尝试稍后正确绑定blob，但由于您的查询未正确写入，因此无效。

//Although you try to bind a blob here it does not get bound
//to anything since you do not include a parameter template.
sqlite3_bind_blob(addStatement, 1, [imageData bytes], [imageData length], SQLITE_TRANSIENT);

要解决此问题，这是一个最小的例子：

//query does not need to be an NSString* but just a const char *
//replace all %@ with ?
const char *sql = "INSERT INTO AnimalsTable(name, ..., imageData) values(?, ..., ?)";
if (sqlite3_open([appDelegate.sqlFile UTF8String],&database)==SQLITE_OK) {
        sqlite3_prepare_v2(database,insert_stmt,-1,&addStatement,NULL);

        //Bind all of the values here before you execute the statement
        sqlite3_bind_text(addStatement, 1, [nameString UTF8String], -1, NULL);
        ...
        sqlite3_bind_blob(addStatement, 9, [imageData bytes], [imageData length], SQLITE_TRANSIENT);

        if (sqlite3_step(addStatement)==SQLITE_DONE) {
            NSLog(@"Data saved");
        }
        ...

        //You must finalize your statement before closing the database
        sqlite3_finalize(addStatement);
        sqlite3_close(database);

使用绑定值有助于防止插入可能是SQL注入攻击的无效数据，并提高经常运行的查询的查询性能。

注意*：如果您打算做很多SQL，请考虑使用FMDB甚至核心数据。

从sqlite检索BLOB映像

1 个答案: