Question

如何更改Inlines类中字段的选择？我不能在Inlines中使用formfield_for_choice_field，那么使用什么？我必须在管理员中生成它，因为我需要传递请求。

Answer 1

如果您的字段是具有choices属性的IntegerField或Charfield，则可以使用以下内容覆盖内联类中的 formfield_for_choice_field 方法：

class YourInline(admin.StackedInline): # or TabularInline
    model = YourModelName

    def formfield_for_choice_field(self, db_field, request=None, **kwargs):
        if db_field.name == 'YOUR_FIELD_NAME':
            kwargs['choices'] = (('', '---------'), ('1', 'Choice1'), ('2', 'Choice2'))
        return db_field.formfield(**kwargs)

祝你好运

Answer 2

我同意eos87的回答。然而，这只是部分解决方案。保存时，由于原始模型的选择用于验证，因此会发生验证错误。要解决该问题，请将此功能添加到模型中：

def clean_fields(self, exclude=None):
    exclude.append('YOUR_FIELD_NAME') # we will do our own validation on this field
    super(YOUR_MODEL, self).clean_fields(exclude = exclude)

    value = self.YOUR_FIELD_NAME
    if value and not self.validChoice(value):
        msg = 'Select a valid choice. %s is not one of the available choices.'
        errors = {''YOUR_FIELD_NAME'': ([msg % value])}
        raise ValidationError(errors)

def validChoice(self, value):
  # add your validation code here

Answer 3

在我的情况下，必须填写表格选项，希望帮助任何人。

# admin.py
class YourInlineForm(forms.ModelForm):
    class Meta:
        fields = '__all__'
        model = YourModelName
        widgets = {
            'level': forms.widgets.Select(
                choices = (
                    (0,'A'),
                    (1,'B'),
                    (2,'C'),
                ),
            )
        }

# admin.py
class YourInline(admin.StackedInline): # or TabularInline
    model = YourModelName
    form = YourInlineForm

    def formfield_for_choice_field(self, db_field, request=None, **kwargs):
        if db_field.name == 'YOUR_FIELD_NAME':
            kwargs['choices'] = (('', '---------'), ('1', 'Choice1'), ('2', 'Choice2'))
        return db_field.formfield(**kwargs)

Django admin - 如何改变内联的选择？

3 个答案: