根据可用数据获得交叉表格报告 - pivot

Question

我想转动并转动现有表格并生成报告（交叉列表）。您会看到vals列由date_a和date_e列的唯一组合决定。我不知道该怎么做。

Answer 1

这样的事情：

测试数据

CREATE TABLE #tbl(date_a DATE,date_e DATE, vals FLOAT)

INSERT INTO #tbl
VALUES
    ('2/29/2012','1/1/2013',28.47),
    ('2/29/2012','2/1/2013',27.42),
    ('2/29/2012','3/1/2013',24.36),
    ('3/1/2012','1/1/2013',28.5),
    ('3/1/2012','2/1/2013',27.35),
    ('3/1/2012','3/1/2013',24.39),
    ('3/6/2012','1/1/2013',27.75),
    ('3/6/2012','2/1/2013',26.63),
    ('3/6/2012','3/1/2013',23.66)

<强>查询

SELECT
    *
FROM
(   
    SELECT
        tbl.date_a,
        tbl.date_e,
        vals
    FROM
        #tbl AS tbl
) AS SourceTable
PIVOT
(
    SUM(vals)
    FOR date_e IN ([1/1/2013],[2/1/2013],[3/1/2013])
) AS pvt

DROP TABLE #tbl

修改

如果你不知道有多少列，那么你需要做一个动态的pivot。像这样：

唯一列

DECLARE @cols VARCHAR(MAX)
;WITH CTE
AS
(
    SELECT
        ROW_NUMBER() OVER(PARTITION BY date_e ORDER BY date_e) AS RowNbr,
        tbl.*
    FROM
        #tbl AS tbl
)
SELECT @cols=STUFF
(
    (
        SELECT 
            ',' +QUOTENAME(date_e)
        FROM
            CTE
        WHERE
            CTE.RowNbr=1
        FOR XML PATH('')
    )
,1,1,'')

动态支点

DECLARE @query NVARCHAR(4000)=
N'SELECT
    *
FROM
(   
    SELECT
        tbl.date_a,
        tbl.date_e,
        vals
    FROM
        #tbl AS tbl
) AS SourceTable
PIVOT
(
    SUM(vals)
    FOR date_e IN ('+@cols+')
) AS pvt'
EXECUTE(@query)