Question

当我尝试对我的代码的某些部分进行单元测试时，我需要一个用户才能登录。为了减少我使用django_factory_boy用户工厂的灯具数量，但生成的用户无法进行身份验证。

from django_factory_boy.auth import UserF
from django.contrib.auth import authenticate

user = UserF()
user.set_password('password')

然后authenticate(username=user.username, password='password')返回None而不是用户。关于这里缺少什么的想法？

Answer 1

另一种方法：

import factory
from django.contrib.auth.hashers import make_password
from somewhere import YourUserModel

class UserF(factory.django.DjangoModelFactory):
    FACTORY_FOR = YourUserModel
    first_name = factory.Sequence(lambda n: "First%s" % n)
    last_name = factory.Sequence(lambda n: "Last%s" % n)
    email = factory.Sequence(lambda n: "email%s@example.com" % n)
    username = factory.Sequence(lambda n: "email%s@example.com" % n)
    password = make_password("password")
    is_staff = False

>>> u = UserF.create()
>>> u.check_password("password")
True

>>> p = UserF.create(password=make_password("password2"))
>>> p.check_password("password2")
True

Answer 2

@ Andrew-Magee解决方案有效，但这里解决方案describe in the doc：

import factory
from django.contrib.auth.models import User
#or
#from somewhere import CustomUser as User

class UserFactory(factory.DjangoModelFactory):
    FACTORY_FOR = User

    username = 'UserFactory'
    email = 'test@example.com'
    password = factory.PostGenerationMethodCall('set_password', 'password')

Django控制台：

>>> from tests.factories import UserFactory
>>> from django.contrib.auth.models import check_password
>>> user = UserFactory()
>>> user.email
'test@example.com'
>>> check_password('password', user.password)
True

>>> user2 = UserFactory(username="SecondUserFactory", email='otheremail@example.com', password="ComplexPasswordMuchLonger!")
>>> user2.email
'otheremail@example.com'
>>> check_password('ComplexPasswordMuchLonger!', user2.password)
True

Answer 3

您应该在user.save()之后致电user.set_password()，因为set_password本身不会保存用户，只会设置数据。

使用Django factory_boy进行测试时的用户身份验证

3 个答案: