我想从文件中读取大量BitSet
个对象(12MB)。我使用下面的代码但只读取文件中的第一个对象并重复它。谢谢
public static void main(String[] args) {
// TODO code application logic here
ObjectInputStream Input = null;
FileInputStream Database = null;
Object Buffer = null;
BitSet H = null;
try
{
Database = new FileInputStream("BloomFilters.txt");
Input = new ObjectInputStream(Database);
while((Buffer = Input.readObject()) != null)
{
H = (BitSet)Buffer;
System.out.println(H);
System.out.println("Yes" );
}
}
catch(Exception e)
{
System.out.println("Exp = " + e.getMessage());
}
以下代码创建一个BitSet对象文件,我想要从这个文件中读取对象
public class Main {
public static void main(String[] args) {
BloomFilter Set = new BloomFilter(512, 100);
ObjectOutputStream Output = null;
DataInputStream Input = null;
FileOutputStream DBOut = null;
FileInputStream DBIn = null;
String Sequence = "";
try
{
DBOut = new FileOutputStream("Bloomfilters.txt");
Output = new ObjectOutputStream(DBOut);
DBIn = new FileInputStream("DB.txt");
Input = new DataInputStream(DBIn);
while((Sequence = (String) Input.readLine()) != null)
{
Set.clear();
for(int i = 0; i < Sequence.length() - 1; i++)
Set.add((Sequence.substring(i, i + 2)));
BitSet buffer = Set.getBitSet();
Output.writeObject(buffer);
}
Input.close();
Output.close();
}
catch(Exception e)
{
System.out.println(e.getMessage());
}
}
}
答案 0 :(得分:0)
我认为您需要扫描程序才能看到此代码Java Bitset error with large index。这是一个不同的问题,但第一个循环是将一个带有数字的大文件读入一个位集,