Question

ALTER TRIGGER [dbo].[AlertMail_tr]
ON 
[dbo].[MethodToLog_tbl]
AFTER INSERT 
AS      
BEGIN
DECLARE @LogId int
SET @LogId = (SELECT LogDataId FROM inserted)
if(SELECT Failure_flag FROM inserted)=1
begin
        exec [DB].[dbo].SendMail_prc
        @Command='EXEC CheckNew.dbo.FailureMail_prc @LogId'
        ,@MailPriority=1
        ,@MailRecipients='abc@xyz.com'
        ,@Subject='Alert-Failure'

end
END

我收到此错误：

必须声明标量变量@LogId。

Answer 1

@Command='EXEC CheckNew.dbo.FailureMail_prc @LogId='+cast ( @LogId as nvarchar(100))

或

@Command='EXEC CheckNew.dbo.FailureMail_prc '+cast ( @LogId as nvarchar(100))

另外，

在@LogId 之前将值放在之前执行字符串查询。

修改

declare @tmp nvarchar(max)
set @tmp='EXEC CheckNew.dbo.FailureMail_prc '+cast (@LogId as nvarchar(100))



 exec [DB].[dbo].SendMail_prc
        @Command=@tmp
        ,@MailPriority=1
        ,@MailRecipients='abc@xyz.com'
        ,@Subject='Alert-Failure'

Answer 2

您的@LogId变量在EXEC命令的范围内不存在。它只看到里面的内容，所以就音乐会而言，DECLARE @LogId int行不存在。

您需要传递已经包含变量值的字符串。

declare @aux varchar(100)
set @aux ='EXEC CheckNew.dbo.FailureMail_prc '+cast ( @LogId as varchar(10)) 

        exec [DB].[dbo].SendMail_prc
        @Command=@aux
        ,@MailPriority=1
        ,@MailRecipients='abc@xyz.com'
        ,@Subject='Alert-Failure'

当然，根据需要更正长度

SQL触发器抛出错误

2 个答案:

修改