Question

我将arraylist从android发送到php。我想取代旧的男人气球作为新的男人气球。在我的表中包含两列1.menuimage 2.menuname ..我想只更新新的menunames

我的表格结构

                  test(table name)
           menucode     menuimage   menuname
             1            image       p
             2              "         q
             3              "          r
             4              "          s
             5              "           t

我想根据菜单代码仅更新menuname ...我正在传递菜单代码[1,2,3,4,5,6,7] ......

<?php

   $old_menu_code = explode(",", str_replace(array("[","]"), "", $_POST['menucode']));
   $new_menu_names = explode(",", str_replace(array("[","]"), "", $_POST['editmainmenu']));
  mysql_connect("localhost", "root", "root");
  mysql_select_db("test");
  foreach ($old_menu_names as $key => $old_name) {
  $new_name = mysql_real_escape_string($new_menu_names[$key]);
  $old_code = mysql_real_escape_string($old_menu_code[$key]);

  mysql_query("UPDATE `test` SET `menuname` = '$new_name' WHERE menucode= '$old_code'") or die('Error' . mysql_error());
echo "Updated";
   }
  ?>

上面的代码测试是数据库包含测试表。在测试表中包含两列一个menuimage和menuname。在menuimage中包含7个图像，menuname包含7个menunmaes。我只想更新menuinames。但上面的代码只更新第一行menunames列。剩下的行没有更新..请问我做了什么错误

Answer 1

您可以使用str_replace＆amp; explode实现你想要的......

吐痰数据

$old_menu_names = "[p,q,r,s,t,u]" ; // or $old_menu_names = $_POST['menuname'] ;
$new_menu_names = "[a,b,c,d,e,f]" ; // or $new_menu_names = $_POST['editmainmenu'] ;

$old_menu_names = explode(",", str_replace(array("[","]"), "", $old_menu_names));
$new_menu_names = explode(",", str_replace(array("[","]"), "", $new_menu_names));

SQL错误

 mysql_query("UPDATE `test` SET `menuname` = '$new_name' WHERE menuname = '$old_name'")

由于您尝试更新条件menuname

中使用的归档WHERE menuname =，因此哪些陈述不起作用

我建议您将其更改为memuid，如果它存在于您的表格中或首先获取ID并使用它来更新它。

编辑1

更新代码

$mysql = new mysqli("localhost","root","root","test");
$sql = "SELECT menucode FROM test where menuname = '%s' ";

foreach ($old_menu_names as $key => $old_name) {
    $new_name = mysql_real_escape_string($new_menu_names[$key]);
    $old_code = mysql_real_escape_string($old_menu_names[$key]);
    $result = $mysql->query(sprintf($sql,$old_code))->fetch_assoc();

    if(!empty($result['menucode']))
    {
        $mysql->query(sprintf("UPDATE `test` SET `menuname` = '%s' WHERE menucode= '%d'",$new_name,$result['menucode']));
        echo "Updated " , $mysql->affected_rows .  PHP_EOL;
    }
    else
    {
        echo "Missing menucode for $old_code " , PHP_EOL;
    }
 }

我希望这会有所帮助

使用php在mysql数据库中更新arraylist时出错

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