Question

以下方法在读取HttpResponse时会出现错误：“已消耗内容”。我知道内容只能被消耗一次，但是我在第一次尝试时遇到了这个错误，我没有在代码中看到我可能会消耗它两次。

    private static String getData(String url, HttpParams params) {
    StringBuilder builder = new StringBuilder();
        HttpClient client = new DefaultHttpClient();
        HttpGet httpGet = new HttpGet(url);
        if (params != null) {
            httpGet.setParams(params);
        }
        String result = "";
        try {
            HttpResponse response = client.execute(httpGet);
            StatusLine statusLine = response.getStatusLine();
            int statusCode = statusLine.getStatusCode();
            if (statusCode == 200) {
                HttpEntity entity = response.getEntity();
                InputStream content = entity.getContent();
                BufferedReader reader = new BufferedReader(new InputStreamReader(content));
                String line;
                while ((line = reader.readLine()) != null) {
                    builder.append(line);
                }
                content.close();
                result = builder.toString();
            } 
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (Exception e) {
            e.printStackTrace();
        }
    return result;  
    }

Answer 1

确保您在Eclipse观看视图中没有类似 http_response.getEntity（）的内容如果你这样做，那么这就是消耗你的流......

Answer 2

这是在模拟器中还是在手机上？它可能是模拟器特定的问题。我在我的设备上测试它，它完美无缺。

您是否有可能正在使用内容的调试器手表？

Answer 3

如果您多次使用该实体，可能会发生这种情况，与此类似：

EntityUtils.toString(entity, HTTP.UTF_8))

Answer 4

您的获取Data（）方法非常完美且工作正常我已经使用此代码进行检查，并且它对我来说非常适合。

所以可能有两次调用此方法的可能性。如果你想检查我在下面使用的检查代码，我会得到完美的结果。

package com.sandeeppatel.httpget;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.StatusLine;
import org.apache.http.client.ClientProtocolException; 
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;

import android.app.Activity;
import android.os.Bundle;

public class HttpGetActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    StringBuilder builder = new StringBuilder();
    HttpClient client = new DefaultHttpClient();
    HttpGet httpGet = new HttpGet("http://www.vogella.com");
    /*if (params != null) {
        httpGet.setParams(params);
    }*/
    String result = "";
    try {
        HttpResponse response = client.execute(httpGet);
        StatusLine statusLine = response.getStatusLine();
        int statusCode = statusLine.getStatusCode();
        if (statusCode == 200) {
            HttpEntity entity = response.getEntity();
            InputStream content = entity.getContent();
            BufferedReader reader = new BufferedReader(new InputStreamReader(content));
            String line;
            while ((line = reader.readLine()) != null) {
                builder.append(line);
            }
            content.close();
            result = builder.toString();
        } 
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (Exception e) {
        e.printStackTrace();
    }
 // return result;  
}
}

我只是在网上获得许可。如果你没有得到这个，请给我你的网址和参数。

Answer 5

我认为你的代码是对的。但尝试这个从HttpEntity访问字符串： String response_str = EntityUtils.toString（responseEntity，HTTP.UTF_8）;

像我在我的方法中使用的那样：

    public String SetObjectSecurity(String username, String password,
        String clientName,String docRid,String ObjectRidsForCheckSum) throws JSONException, ClientProtocolException, IOException
{
    String SetObjectSecurityURL = "url";
    StringEntity str_request_entity = null;
    HttpResponse http_response = null;

    HttpGet getrequest = new HttpGet(SetObjectSecurityURL);
    postrequest.setHeader("Accept", "application/json");
    postrequest.setHeader("Content-type", "application/json");
//set param here


    HttpClient httpClient = new DefaultHttpClient();

    http_response = httpClient.execute(getrequest);

    //Log.e("Status code ",http_response);
    HttpEntity responseEntity = http_response.getEntity();

    String response_str =EntityUtils.toString(responseEntity, HTTP.UTF_8);
    Log.e("output",response_str);
    int i = http_response.getStatusLine().getStatusCode();
    Log.e("status","code "+i);


if(i==this){

do this}
else
{
this
}       
        return response_str;
        }

Android HttpResponse - 已消耗内容

5 个答案: