我想编写一个python脚本,一次创建几个字典,然后打印字典,但我不知道如何将字符串转换为变量。
number = 0
while (number < 10):
number = number + 1
dictionarynumber = ("D"+str(number)) # creates the dictionarys name(D1,D2,D3,D4,D5,D6,D7,D8,D9,D10)
var(dictionarynumber) = {"Fruit":"Apple","Book":"Oliver Twist","Building":"White House"} #Of course var() doesn't work but I placed it here to get my point across
print(dictionarynumber)
回答后:
我喜欢关于字典的想法,并且删除不需要的“D”是有道理的。你们怎么看待这个?
dict = {}
n = 0
while (n < 10):
n = n + 1
d = n
d = {"Key":"Information"}
dict[n] = d
print(dict)
# Output =
# {1: {'Key': 'Information'},
# 2: {'Key': 'Information'},
# 3: {'Key': 'Information'},
# 4: {'Key': 'Information'},
# 5: {'Key': 'Information'},
# 6: {'Key': 'Information'},
# 7: {'Key': 'Information'},
# 8: {'Key': 'Information'},
# 9: {'Key': 'Information'},
# 10: {'Key': 'Information'}}
答案 0 :(得分:4)
如果您想为每个字典命名,请将它们放在字典中。
dicts = {}
# dict_list = []
for i in xrange(10):
dictionary_key = ('d{0}'.format(i))
dict_item = {"Fruit":"Apple","Book":"Oliver Twist","Building":"White House"}
dicts[dictionary_key] = dict_item
# dict_list.append(dict_item)
如果您没有使用词典的名称,请将它们放在列表中。
答案 1 :(得分:0)
您似乎正在尝试创建混合数据类型,但我不清楚您想要什么样的结构,所以我会给你2个答案,希望一个是正确的。
第1,如果您正在尝试创建一堆字典并打印它,您可以这样做:
diclist = [{"Fruit":"Apple"},{"Book":"Oliver Twist"},{"Building":"White House"}]
print(diclist[1])
第二,按照你给出的例子,可能是为了创建一个列表字典。例如
listDic = {'Fruit':['Apples', 'Bannanas', 'Durian'], 'Book':['Oliver Twist','Flashman', 'Catch 22']}
print (listDic)
你可以像这样访问它:
print(listDic['Fruit'])
会导致
['苹果','Bannanas','榴莲']
这个 打印(listDic [ '果实'] [1]) 会导致
Bannanas
如果我错过了您想要的答案,或者您想要更多细节,请发表评论。