Question

我正在尝试将数据从客户端套接字发送到服务器，但是，当发送数据时，服务器仍在等待数据，之后客户端套接字然后等待来自服务器的数据。有两个插座互相等待。有人可以解释什么是错的：

客户端：

package ssd8ex3_tcp_client;

import java.io.*;
import java.net.*;

public class Ssd8Ex3_TCP_Client {

    private static final int SERVICE_PORT = 2000;

    public static void main(String[] args) {

        String hostname = "localhost";

        int counter = 0;
        while (counter < 1000) {
            try {
                Socket socket = new Socket(hostname, SERVICE_PORT);
                socket.setSoTimeout(50000);
                PrintStream pstream = new PrintStream( socket.getOutputStream() );
                pstream.print(counter);
                pstream.flush();

                BufferedReader reader = new BufferedReader(new InputStreamReader(socket.getInputStream()));
                String s = reader.readLine();
                System.out.println("Results :" + s);
                socket.close();

            } catch (IOException e) {
                e.printStackTrace();
            }

            counter++;
        }

    }
}

服务器：

package ssd8ex3_tcp_server;

import java.io.*;
import java.net.*;


public class Ssd8Ex3_TCP_Server {

    public static final int SERVICE_PORT = 2000;

    public static void main(String[] args) {
        try {
            ServerSocket server_socket = new ServerSocket(SERVICE_PORT);

            System.out.println("Server started");

            for(;;){
                Socket nextClient = server_socket.accept();
                System.out.println("Received request from " + nextClient.getInetAddress() + ":" + nextClient.getPort());

                BufferedReader reader = new BufferedReader(new InputStreamReader(nextClient.getInputStream()));
                String s = reader.readLine();
                OutputStreamWriter out = new OutputStreamWriter(nextClient.getOutputStream());
                PrintWriter pout = new PrintWriter(out);

                pout.print(s);

                out.flush();

                nextClient.close();
            }

        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

Answer 1

您的服务器使用readLine，它将等待一整行。您的客户使用的print不会附加行尾标记。所以服务器正在等待该行尾。

在客户端使用println（并为返回交换执行相同操作），事情应该“解开”。

tcp客户端和服务器不会相互接收数据

1 个答案: