你能给我一个查询,它将varchars类型的行值转换为带有任何分隔符的单个列。 例如 有2列的表
col1 |col2
1 | m10
1 | m31
2 | m20
2 | m50
现在我希望输出为
col1| col2
1|m10:m31
2|m20:m50
答案 0 :(得分:0)
一种方法是使用游标。
使用光标,您可以一次获取一行!
伪代码将是:
if actual_col1 = last_col1
then col2_value = col2_value + actual_col2
else
insert into #temptable value(col1, col2_value)
col2_value = actual_col2
end
检查HERE以了解如何使用它们。
答案 1 :(得分:0)
你总是有配对,不能再少了吗?
select
col1,
count(*)
from table
group by col1
having count(*) <> 2
会给你零结果吗?
如果是这样,你可以自己加入......
declare @delimiter varchar(1)
set @delimiter = :
select
t1.col1, t1.col2 + @delimiter + t2.col2
from tablename t1
inner join tablename t2
on t1.col1 = t2.col1
and t1.col2 <> t2.col2
答案 2 :(得分:0)
使用此解决方案:
SELECT列表(col2,&#39;:&#39;)作为col2 FROM table_name group by col1;
答案 3 :(得分:0)
请使用以下逻辑,表#t1
将成为最终表。
create table #t123(a char(2), b char(2))
go
create table #t1(a char(2), c char(100) default '')
go
Insert into #t123 values ('a','1')
Insert into #t123 values ('a','2')
Insert into #t123 values ('a','3')
Insert into #t123 values ('b','1')
Insert into #t123 values ('c','1')
Insert into #t123 values ('d','1')
Insert into #t123 values ('d','1')
go
insert into #t1 (a) Select distinct a from #t123
go
Select distinct row_id = identity(8), a into #t1234 from #t123
go
Declare @a int, @b int, @c int, @d int, @e int, @f char(2), @g char(2), @h char(2)
Select @a =min(row_id), @b=max(row_id) from #t1234
While @a <= @b
Begin
Select @f = a , @h = '', @g = '' from #t1234 where row_id = @a
Update #t1 set c = '' where a = @f
Select row_id = identity(8), b into #t12345 from #t123 where a = @f
Select @c =min(row_id), @d=max(row_id) from #t12345
While @c <= @d
begin
Select @g = b from #t12345 where row_id = @d
Update #t1 set c = @g +' '+ c where a = @f --change delimiter
Select @d = @d-1
End
Drop table #t12345
Select @a = @a+1
End
go
Select * from #t1 -- final table with transposed values