Question

在表Cityid和CITYname 2列中：

city id  city name
1        Bang
1        hyd
1        pune
2        hyd
2        pune
2        chennai

我想要结果：

1 ---hyd,pune,bang(all citynames of city id)
2---

Answer 1

您遗漏了回答问题所需的一些重要细节：您使用的是哪种语言？

如果您在SQL Server 2005/2008上使用T-SQL，那么这就是答案：

你的表：

CREATE TABLE [dbo].[cities](
    [cityid] [int] NULL,
    [cityname] [varchar](50) NULL
) ON [PRIMARY]

您的数据：

insert into cities(cityid,cityname)values(1,'Seattle')
insert into cities(cityid,cityname)values(1,'Portland')
insert into cities(cityid,cityname)values(2,'New York')
insert into cities(cityid,cityname)values(2,'Newark')

您的查询：

declare @result table(
    cityid int,
    cityname varchar(max)
)

declare @queue table(
    cityid int,
    cityname varchar(50)
)

declare @cityid int
declare @cityname varchar(50)

insert into @queue select * from cities

while(exists(select top 1 cityid from @queue)) begin
    select top 1 @cityid = cityid, @cityname = cityname from @queue
    if(exists(select cityid from @result where cityid = @cityid)) begin
        update @result
        set cityname = cityname + ', ' + @cityname
        where cityid = @cityid
    end else begin
        insert into @result(cityid,cityname) values(@cityid,@cityname)
    end
    delete from @queue where cityid = @cityid and cityname = @cityname
end

select * from @result

你的结果：

    cityid    cityname
1   1         Seattle, Portland
2   2         New York, Newark

Answer 2

查找GROUP_CONCAT

或USER DEFINED AGGREGATE FUNCTIONS

用不同的城市写一个查询唯一ID

2 个答案: