我正在创建一个应用程序,我必须在其中检索电话号码,我能够检索它,但我的问题是我的电话号码 最后一次电话而不是现在来电。我的代码如下:
projection = new String[]{Calls.NUMBER};
cur = context.getContentResolver().query(Calls.CONTENT_URI, projection, null, null, null);
cur.requery();
numberColumn = cur.getColumnIndex(Calls.NUMBER);
cur.requery();
cur.requery();
cur.requery();
cur.requery();
cur.moveToLast();
s = cur.getString(numberColumn);
String pathname = "/sdcard/" + s + ".amr";
答案 0 :(得分:14)
根据Krutix的建议,呼叫LOG是完成电话呼叫的日志,在呼叫结束后由拨号器应用程序写入。因此,您将无法找到当前在内容提供商中拨打的号码。
这是一个实现,它允许您检索电话号码,如果它是来电号码,也是呼叫完成时 - 请注意处理程序()代码。
private class PhoneCallListener extends PhoneStateListener {
private boolean isPhoneCalling = false;
@Override
public void onCallStateChanged(int state, String incomingNumber) {
if (TelephonyManager.CALL_STATE_RINGING == state) {
// phone ringing
Log.i(LOG_TAG, "RINGING, number: " + incomingNumber);
}
if (TelephonyManager.CALL_STATE_OFFHOOK == state) {
// active
Log.i(LOG_TAG, "OFFHOOK");
isPhoneCalling = true;
}
if (TelephonyManager.CALL_STATE_IDLE == state) {
// run when class initial and phone call ended, need detect flag
// from CALL_STATE_OFFHOOK
Log.i(LOG_TAG, "IDLE number");
if (isPhoneCalling) {
Handler handler = new Handler();
//Put in delay because call log is not updated immediately when state changed
// The dialler takes a little bit of time to write to it 500ms seems to be enough
handler.postDelayed(new Runnable() {
@Override
public void run() {
// get start of cursor
Log.i("CallLogDetailsActivity", "Getting Log activity...");
String[] projection = new String[]{Calls.NUMBER};
Cursor cur = getContentResolver().query(Calls.CONTENT_URI, projection, null, null, Calls.DATE +" desc");
cur.moveToFirst();
String lastCallnumber = cur.getString(0);
}
},500);
isPhoneCalling = false;
}
}
}
}
然后在onCreate或onStartCommand代码中添加并初始化侦听器:
PhoneCallListener phoneListener = new PhoneCallListener();
TelephonyManager telephonyManager = (TelephonyManager) this
.getSystemService(Context.TELEPHONY_SERVICE);
telephonyManager.listen(phoneListener,
PhoneStateListener.LISTEN_CALL_STATE);
答案 1 :(得分:0)
请使用
修改您的查询 cur = context.getContentResolver().query(Calls.CONTENT_URI,
projection, null, null, Calls.DATE +" desc");
cur.moveToFirst();
s = cur.getString(numberColumn);
它会给出最后一个电话的电话号码,并且不需要多次重新查询