右手迷宫在C中遍历

时间:2012-04-12 21:56:20

标签: c

这是我的第一个问题,是的,这是一项“家庭作业”任务。我已经工作了几个小时但无法使算法工作。我编写的程序应该包含一个接受12乘12阵列的函数,并找到结束的路径。主函数找到迷宫的开始并将其改为“x”以表示“玩家”的位置。然后主函数调用接受数组的mazePrint函数在清除屏幕后打印它。然后它调用接受数组的mazeTraversal函数。 mazeTraversal的第一部分尝试定位“x”的位置并用“。”替换它。下一部分应该确定“x”面向哪个方向。我用了4,5,6和8(西,南,东,北(看数字键))来表示它面对的方式。在此基础上面临的方式,mazeTraversal试图确定是否有一个开放的路径正确的,那么在前面,然后向左,然后背后,并随后把一个X在那个位置,改变x是路面对。在我运行程序的第二步之后出了点问题。感谢您的帮助,如果不是这样的问题,请抱歉。

#include <stdio.h>
#include <stdlib.h>

void mazePrint(char *maze[12][12]);
void mazeTraversal(char *maze[12][12]);
static int face = 6;

main()
{
    int i = 0;
    int j = 0; 
    int k = 0;
    int start;
    int xpos;

    char *mazeone[12][12] = {
       //0///1///2///3///4///5///6///7///8///9///10//11///
        "#","#","#","#","#","#","#","#","#","#","#","#",//0
        "#",".",".",".","#",".",".",".",".",".",".","#",//1
        ".",".","#",".","#",".","#","#","#","#",".","#",//2
        "#","#","#",".","#",".",".",".",".","#",".","#",//3
        "#",".",".",".",".","#","#","#",".","#",".",".",//4
        "#","#","#","#",".","#",".","#",".","#",".","#",//5
        "#","#",".","#",".","#",".","#",".","#",".","#",//6
        "#","#",".","#",".","#",".","#",".","#",".","#",//7
        "#",".",".",".",".",".",".",".",".","#",".","#",//8
        "#","#","#","#","#","#",".","#","#","#",".","#",//9
        "#",".",".",".",".",".",".","#",".",".",".","#",//10
        "#","#","#","#","#","#","#","#","#","#","#","#",};//11

    for (i = 0; i <12; i++)
        if (mazeone[i][0] == "." ) {
            start = i; 
            mazeone[start][0] = "x";
            xpos = start;
            break;
        }

    printf("X is the starting point.\n");
    printf("Press Space Bar to watch the X move.\n\n\n");
    getchar();
    mazePrint(mazeone);
    getchar();
    return 0;
}

void mazePrint(char *maze[12][12])
{   
    int x = 0; 
    int y = 0;

    system("cls");
    for (x = 0; x < 12; x++) {
        for (y = 0; y < 12; y++) {
            printf("%s", maze[x][y]);
        }
        printf("\n"); 
    }
    getchar(); 
    mazeTraversal(maze);
}

void mazeTraversal(char *maze[12][12])
{
    int x = 0; 
    int y = 0;

    for (x = 0; x < 12; x++) {
        for (y = 0; y < 12; y++) {
            if (maze[y][x] == "x")
                break;
        } 
        if(maze[y][x] == "x")
            break;
    }

    for (y = 0; y < 12; y++) {
        for (x = 0; x < 12; x++) {
            if (maze[y][x] == "x")
                break;
        } 
        if (maze[y][x] == "x")
            break;
    }

    maze[y][x] = ".";

    switch (face) {
        case 6:{
            if (maze[y][x-1] == ".") {
                maze[y][x-1] = "x"; 
                face = 5;
            } else if (maze[y + 1][x] == ".") {
                maze[y + 1][x] = "x"; 
                face = 6;
            } else if (maze[y][x+1] == ".") {
                maze[y][x+1] = "x";
                face = 8;
            } else if (maze[y - 1][x] == ".") {
                maze[y - 1][x] = "x"; 
                face = 4;
            }
        }
        case 8:{
            if (maze[y + 1][x] == ".") {
                maze[y + 1][x] = "x"; 
                face = 6;
            } else if (maze[y][x+1] == ".") {
                maze[y][x+1] = "x";
                face = 8;
            } else if (maze[y - 1][x] == ".") {
                maze[y - 1][x] = "x"; 
                face = 4;
            } else if (maze[y][x-1] == ".") {
                maze[y][x-1] = "x"; 
                face = 5;
            }
        }
        case 4:{
            if (maze[y][x+1] == ".") {
                maze[y][x+1] = "x";
                face = 8;
            } else if (maze[y - 1][x] == ".") {
                maze[y - 1][x] = "x"; 
                face = 4;
            } else if (maze[y][x-1] == ".") {
                maze[y][x-1] = "x"; 
                face = 5;
            } else if (maze[y + 1][x] == ".") {
                maze[y + 1][x] = "x"; 
                face = 6;
            }
        }
        case 5:{
            if (maze[y - 1][x] == ".") {
                maze[y - 1][x] = "x";
                face = 4;
            } else if (maze[y][x-1] == ".") {
                maze[y][x-1] = "x"; 
                face = 5;
            } else if (maze[y + 1][x] == ".") {
                maze[y + 1][x] = "x"; 
                face = 6;
            } else if (maze[y][x+1] == ".") {
                maze[y][x+1] = "x";
                face = 8;
            }
        }
    }

    mazePrint(maze);
}

2 个答案:

答案 0 :(得分:4)

在每个break;代码块之后,您错过了switch(face)中的case:个语句。如果没有break;语句,您的代码将落入下一个case:中的每一个,这不是您想要的。

答案 1 :(得分:3)

我认为你的方向错了。你应该从maze[2][0]开始,面向'6'。你想要前进到maze[2][1],面对仍然是'6'。但是如果你看一下方向6的mazeTraversal代码,就会遇到这种情况:

if(maze[y][x+1] == "."){     
   maze[y][x+1] = "x";     
   face = 8;
 }

因此,您正在错误地设置结果方向 可能有助于保持正确的一件事是使用枚举而不是随机数字代码:

enum Facing {
   face_EAST,
   face_SOUTH,
   face_WEST, 
   face_NORTH } face = face_EAST;

我甚至可能会忘记指南针方向并使用特定问题的指示。这应该有助于在代码中保持方向。

enum Facing {
   face_Xplus,
   face_Yplus, 
   face_Xminus, 
   face_Yminus } face = face_Xplus;