如何将jquery对象合并在一起
我有
{
"merchantcontract":"Ready Reserve Foods 10104.01",
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":15.2600,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
},
{
"merchantcontract":"Ready Reserve Foods 10104.01",
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":2.6000,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
}
我想
{
"merchantcontract":"Ready Reserve Foods 10104.01",
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":15.2600,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
},
{
"merchantcontract":"Ready Reserve Foods 10104.01",
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":2.6000,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
}
{"merchantcontract":"Ready Reserve Foods 10104.01"{
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":15.2600,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
},
{
"merchantcontractid":"c4253769-5a57-e111-b935-00155d010302",
"smi_transactiondate":"\/Date(1332140400000)\/",
"smi_glamount2":2.6000,
"smi_transactionclass":180870001,
"smi_transactionclassname":"Residual Agent Commission",
"smi_contractprodcutidname":"Traditional",
"smi_agentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5",
"smi_primaryagentid":"1d3f44ee-afc3-e011-addf-a4badb1ddef5"
}
}
因此两个对象都在一个对象下。我可能有两个以上的对象。
在jquery中使用每个对象创建对象。
我不知道如何开始这个。
答案 0 :(得分:57)
jQuery的$.extend会做你想做的事。
//merging two objects into new object
var new_object = $.extend({}, object1, object2);
//merge object2 into object1
$.extend(object1, object2);
答案 1 :(得分:8)
anObj={'propone':'1', 'proptwo':'2'};
anotherObj={'propel':'11', 'proptlv':'12'};
var opts = {};
$.extend(opts, anObj, anotherObj, {
bar: "baz",
thing: "foo"
});
console.log(opts);
答案 2 :(得分:3)
如果您希望以递归方式合并它们,$.extend会提供参数deep
。如果deep=true
合并成为递归。上面的一个例子,
// Initialize two objects.
var json1 = { "a": { "a1": "value1", "a2": "value2" }};
var json2 = { "a": { "a3": "value3" }};
// Merge them recursively.
var newJson = $.extend(true, {}, json1, json2);
// Test it.
if (newJson.a.a1 && newJson.a.a3) {
console.log("Success");
}
答案 3 :(得分:0)
你能把它们放在一个数组中吗?
var myObjects = [];
并在每个创建它们的位置添加:
myObjects.push(newObject);
答案 4 :(得分:0)
如果要更新现有对象,请使用:
$.extend(obj1, obj2); //update obj1 and put all obj2 values in it.
$。extend将更改您现有对象的值
要创建一个新的第三个对象即两个对象的总和,可以使用此功能
function merger_objects(obj1,obj2){
$.each(obj2, function(key, value) {
obj1[key] = value;
});
return obj1;
}
示例
var fruit = {apple:"sweet",graps:"bitter"}
var vege = {cucamber:"bitter",letuce:"bitter"}
var fruit_and_vege = merger_objects(fruit,vege);
//returns {apple:"sweet",graps:"bitter",cucamber:"bitter",letuce:"bitter"}