我有两个不同的日期列：detail_returndate和detail_duedate。我试图找到两者之间的差异并将其作为days_overdue返回。
这是基本的SELECT。我尝试过使用diffday并减去2，但我没有太多运气。
select rent_num, vid_num, detail_returndate, detail_duedate
from detailrental
如果您需要表格的完整sql代码，请告诉我，但我认为您不需要它
要明确我需要通过取detail_returndate和detail_duedate之间的差异来找出过期的日子。这应该产生逾期的金额，天数
/* Database Systems, 9th Ed., Coronel/MOrris/Rob */
/* Type of SQL : MySQL */
/*Create table price*/
CREATE TABLE price
(price_code INTEGER PRIMARY KEY AUTO_INCREMENT,
price_description VARCHAR(20) NOT NULL,
price_rentfee DECIMAL(5,2),
price_dailylatefee DECIMAL(5,2));
/*Insert data into price*/
INSERT INTO price VALUES(1,'Standard',2,1);
INSERT INTO price VALUES(2,'New Release',3.5,3);
INSERT INTO price VALUES(3,'Discount',1.5,1);
INSERT INTO price VALUES(4,'Weekly Special',1,.5);
/*Create table movie*/
CREATE TABLE movie
(movie_num INTEGER PRIMARY KEY AUTO_INCREMENT,
movie_title VARCHAR(75) NOT NULL,
movie_year INTEGER,
movie_cost DECIMAL(5,2),
movie_genre VARCHAR(50),
price_code INTEGER,
FOREIGN KEY(price_code) REFERENCES price(price_code));
/*Insert data into movie*/
INSERT INTO movie VALUES(1234,'The Cesar Family Christmas',2007,39.95,'FAMILY',2);
INSERT INTO movie VALUES(1235,'Smokey Mountain Wildlife',2004,59.95,'ACTION',1);
INSERT INTO movie VALUES(1236,'Richard Goodhope',2008,59.95,'DRAMA',2);
INSERT INTO movie VALUES(1237,'Beatnik Fever',2007,29.95,'COMEDY',2);
INSERT INTO movie VALUES(1238,'Constant Companion',2008,89.95,'DRAMA',NULL);
INSERT INTO movie VALUES(1239,'Where Hope Dies',1998,25.49,'DRAMA',3);
INSERT INTO movie VALUES(1245,'Time to Burn',2005,45.49,'ACTION',1);
INSERT INTO movie VALUES(1246,'What He Doesn''t Know',2006,58.29,'COMEDY',1);
/*Create table video*/
CREATE TABLE video
(vid_num INTEGER PRIMARY KEY AUTO_INCREMENT,
vid_indate DATE,
movie_num INTEGER,
FOREIGN KEY(movie_num) REFERENCES movie(movie_num));
/*Insert data into video*/
INSERT INTO video VALUES(54321,'2008-06-18',1234);
INSERT INTO video VALUES(54324,'2008-06-18',1234);
INSERT INTO video VALUES(54325,'2008-06-18',1234);
INSERT INTO video VALUES(34341,'2007-01-22',1235);
INSERT INTO video VALUES(34342,'2007-01-22',1235);
INSERT INTO video VALUES(34366,'2009-03-02',1236);
INSERT INTO video VALUES(34367,'2009-03-02',1236);
INSERT INTO video VALUES(34368,'2009-03-02',1236);
INSERT INTO video VALUES(34369,'2009-03-02',1236);
INSERT INTO video VALUES(44392,'2008-10-21',1237);
INSERT INTO video VALUES(44397,'2008-10-21',1237);
INSERT INTO video VALUES(59237,'2009-02-14',1237);
INSERT INTO video VALUES(61388,'2007-01-25',1239);
INSERT INTO video VALUES(61353,'2006-01-28',1245);
INSERT INTO video VALUES(61354,'2006-01-28',1245);
INSERT INTO video VALUES(61367,'2008-07-30',1246);
INSERT INTO video VALUES(61369,'2008-07-30',1246);
/*Create table membership*/
CREATE TABLE membership
(mem_num INTEGER PRIMARY KEY AUTO_INCREMENT,
mem_fname VARCHAR(30) NOT NULL,
mem_lname VARCHAR(30) NOT NULL,
mem_street VARCHAR(120),
mem_city VARCHAR(50),
mem_state VARCHAR(2),
mem_zip VARCHAR(5),
mem_balance DECIMAL(10,2));
/*Insert data into membership*/
INSERT INTO membership VALUES(102,'Tami','Dawson','2632 Takli Circle','Norene','TN','37136',11);
INSERT INTO membership VALUES(103,'Curt','Knight','4025 Cornell Court','Flatgap','KY','41219',6);
INSERT INTO membership VALUES(104,'Jamal','Melendez','788 East 145th Avenue','Quebeck','TN','38579',0);
INSERT INTO membership VALUES(105,'Iva','Mcclain','6045 Musket Ball Circle','Summit','KY','42783',15);
INSERT INTO membership VALUES(106,'Miranda','Parks','4469 Maxwell Place','Germantown','TN','38183',0);
INSERT INTO membership VALUES(107,'Rosario','Elliott','7578 Danner Avenue','Columbia','TN','38402',5);
INSERT INTO membership VALUES(108,'Mattie','Guy','4390 Evergreen Street','Lily','KY','40740',0);
INSERT INTO membership VALUES(109,'Clint','Ochoa','1711 Elm Street','Greenville','TN','37745',10);
INSERT INTO membership VALUES(110,'Lewis','Rosales','4524 Southwind Circle','Counce','TN','38326',0);
INSERT INTO membership VALUES(111,'Stacy','Mann','2789 East Cook Avenue','Murfreesboro','TN','37132',8);
INSERT INTO membership VALUES(112,'Luis','Trujillo','7267 Melvin Avenue','Heiskell','TN','37754',3);
INSERT INTO membership VALUES(113,'Minnie','Gonzales','6430 Vasili Drive','Williston','TN','38076',0);
/*Create table rental*/
CREATE TABLE rental
(rent_num INTEGER PRIMARY KEY AUTO_INCREMENT,
rent_date DATE,
mem_num INTEGER,
FOREIGN KEY(mem_num) REFERENCES membership(mem_num));
/*Insert data into rental*/
INSERT INTO rental VALUES(1001,'2009-03-01',103);
INSERT INTO rental VALUES(1002,'2009-03-01',105);
INSERT INTO rental VALUES(1003,'2009-03-02',102);
INSERT INTO rental VALUES(1004,'2009-03-02',110);
INSERT INTO rental VALUES(1005,'2009-03-02',111);
INSERT INTO rental VALUES(1006,'2009-03-02',107);
INSERT INTO rental VALUES(1007,'2009-03-02',104);
INSERT INTO rental VALUES(1008,'2009-03-03',105);
INSERT INTO rental VALUES(1009,'2009-03-03',111);
/*Create table detailrental*/
CREATE TABLE detailrental
(rent_num INTEGER,
vid_num INTEGER,
detail_fee DECIMAL(5,2),
detail_duedate DATE,
detail_returndate DATE,
detail_dailylatefee DECIMAL(5,2),
PRIMARY KEY(rent_num, vid_num),
FOREIGN KEY(rent_num) REFERENCES rental(rent_num),
FOREIGN KEY(vid_num) REFERENCES video(vid_num));
/*Insert data into dailyrental*/
INSERT INTO detailrental VALUES(1001,34342,2,'2009-03-04','2009-03-02',1);
INSERT INTO detailrental VALUES(1001,61353,2,'2009-03-04','2009-03-03',1);
INSERT INTO detailrental VALUES(1002,59237,3.5,'2009-03-04','2009-03-04',3);
INSERT INTO detailrental VALUES(1003,54325,3.5,'2009-03-04','2009-03-09',3);
INSERT INTO detailrental VALUES(1003,61369,2,'2009-03-06','2009-03-09',1);
INSERT INTO detailrental VALUES(1003,61388,0,'2009-03-06','2009-03-09',1);
INSERT INTO detailrental VALUES(1004,44392,3.5,'2009-03-05','2009-03-07',3);
INSERT INTO detailrental VALUES(1004,34367,3.5,'2009-03-05','2009-03-07',3);
INSERT INTO detailrental VALUES(1004,34341,2,'2009-03-07','2009-03-07',1);
INSERT INTO detailrental VALUES(1005,34342,2,'2009-03-07','2009-03-05',1);
INSERT INTO detailrental VALUES(1005,44397,3.5,'2009-03-05','2009-03-05',3);
INSERT INTO detailrental VALUES(1006,34366,3.5,'2009-03-05','2009-03-04',3);
INSERT INTO detailrental VALUES(1006,61367,2,'2009-03-07',NULL,1);
INSERT INTO detailrental VALUES(1007,34368,3.5,'2009-03-05',NULL,3);
INSERT INTO detailrental VALUES(1008,34369,3.5,'2009-03-05','2009-03-05',3);
INSERT INTO detailrental VALUES(1009,54324,3.5,'2009-03-05',NULL,3);
INSERT INTO detailrental VALUES(1001,34366,3.5,'2009-03-04','2009-03-02',3);
答案 0 :(得分：2)
SELECT rent_num,
vid_num,
detail_returndate,
detail_duedate,
DATEDIFF( detail_duedate, detail_returndate) as days_overdue
FROM detailrental
答案 1 :(得分：0)
它应该如上所示工作。也许添加必须的`。
SELECT `rent_num`,
`vid_num`,
`detail_returndate`,
`detail_duedate`,
DATEDIFF(`detail_returndate`,`detail_duedate`) as days_overdue
FROM detailrental
此外，DATEDIFF从第一个值中减去第二个值，如图所示，它应该为days_overdue提供一个正数。