Question

PHP新手，特别是OOP。

我有一个User.php类，我在login.php中使用。

$vars = $user->login($email, $pass)

目前我正在调用登录方法，最后我将调用if语句进行验证等。然而，目前，我正在尝试连接到数据库，提取一些信息并将该信息添加到我班级的属性中。我可以将信息拉出来（通过方法login（）中的对象的var_dump验证（$ results的vardump），但由于某些原因，我的当前代码无法更新我的类属性。

这是我的代码

user.php的

<?php

class User {

public $id, $password, $first_name, $last_name;
private $user_level;
protected static $db_fields = array('id', 'first_name', 'last_name', 'pass');
protected static $table_name="users";


public function login($email, $pass) {
    global $database;
    $sql = "SELECT user_id, first_name, last_name, user_level FROM users WHERE (email='$email' AND pass=SHA1('$pass')) AND active IS NULL LIMIT 1";
    $results = self::find_by_sql($sql);
    if (!empty($results)) {
        $this->setuservars($results);
        return array_shift($results);
    } else {
        return false;
    }
//  return !empty($results) ? array_shift($results) : false;
}


private function setuservars($uservariables) {
    $this->id = $uservariables->id;
    $this->first_name = $uservariables->first_name;
    $this->last_name = $uservariables->last_name;
    $this->user_level = $uservariables->user_level;

    }



public static function find_by_sql($sql="") {
    global $database;
    $results_array = $database->query($sql);
    $object_array = array();
    while ($row = $results_array->fetch_assoc()) {
        $object_array[] = self::instantiate($row);
    }
    return $object_array;
}


public function mysqli_array_escape($arg1){
    global $database;
    foreach ($arg1 as $key => $value) {
        $arg1[$key] = $database->real_escape_string($value);
    }
    return $arg1;
}


private static function instantiate($record) {
    // Could check that $record exists and is an array
    $object = new self;
    foreach($record as $attribute=>$value){
        if($object->has_attribute($attribute)) {
            $object->$attribute = $value;
        }
    }
    return $object;
}


private function has_attribute($attribute) {
    return array_key_exists($attribute, $this->attributes());
}

protected function attributes() {
    // return an array of attribute names and their values
    $attributes = array();
    foreach(self::$db_fields as $field) {
        if(property_exists($this, $field)) {
            $attributes[$field] = $this->$field;
        }
    }
    return $attributes;
}

}



$user = new User();


?>

，这是我的login.php（我已经编辑了if语句以验证用户是否已成功登录，我已用“if（1 == 1）{”语句替换以帮助调试代码。

if (isset($_POST['submitted'])) {

$postdata = $user->mysqli_array_escape($_POST);

//var_dump($user->results);

if (((!isset($_POST['email'])) || ($_POST['email']) == '') || (!isset($_POST['pass']) || ($_POST['pass']) == '') ) {
    //error handling eventually
} else { 
    $email = $_POST['email'];
    $pass = $_POST['pass'];
    $vars = $user->login($email, $pass);
    echo $vars->first_name;


    if (1 == 1) {
        echo "you have successfully logged in";
        var_dump($user->id);

    } else { 
        echo "not logged in"; 
    }
}   

}

哦，我收到的当前错误是“第26行脚本'F：\ internet \ www \ htdocs \ blissoop \ classes \ User.php'发生错误：试图获取非对象的属性日期/时间：2012年4月13日05:01:09“

Answer 1

我已在此问题的帮助下解决了这个问题

这是帮助的代码：Get value from Multidimentional Array containing an Object。

我给答案提供了+1的帮助。

foreach ($array as $item) {
$userId = $item->user_id;
//do something with the userId for this item
}

我必须遍历数组才能获得对象的属性。

PHP OOP无法编辑类属性

1 个答案: