我正在开发一项服务,其中发件人支付金额,其中95%发送给一个接收者,5%发送给另一个接收者。 (例如,100美元的付款,95美元的主要费用和5美元的中学费用。)在这个例子中,发送者看到95美元作为他的支付金额而不是100美元,我不明白为什么。
这是在与另一个Paypal电子邮件地址数组对应的数组中设置金额的位置。
$receiverAmountArray = array(
.5*$backing_amount,
.95*$backing_amount
);
第二个电子邮件地址设置为主要。最大数量的接收者必须是主要接收者。
$receiverPrimaryArray = array(
'false',
'true'
);
CallPay(来自Paypal的图书馆)被称为:
$resArray = CallPay ($actionType, $cancelUrl, $returnUrl, $currencyCode, $receiverEmailArray,
$receiverAmountArray, $receiverPrimaryArray, $receiverInvoiceIdArray,
$feesPayer, $ipnNotificationUrl, $memo, $pin, $preapprovalKey,
$reverseAllParallelPaymentsOnError, $senderEmail, $trackingId
);
这是CallPay功能。抱歉长度:
function CallPay( $actionType, $cancelUrl, $returnUrl, $currencyCode, $receiverEmailArray, $receiverAmountArray,
$receiverPrimaryArray, $receiverInvoiceIdArray, $feesPayer, $ipnNotificationUrl,
$memo, $pin, $preapprovalKey, $reverseAllParallelPaymentsOnError, $senderEmail, $trackingId )
{
/* Gather the information to make the Pay call.
The variable nvpstr holds the name value pairs
*/
// required fields
$nvpstr = "actionType=" . urlencode($actionType) . "¤cyCode=" . urlencode($currencyCode);
$nvpstr .= "&returnUrl=" . urlencode($returnUrl) . "&cancelUrl=" . urlencode($cancelUrl);
if (0 != count($receiverAmountArray))
{
reset($receiverAmountArray);
while (list($key, $value) = each($receiverAmountArray))
{
if ("" != $value)
{
$nvpstr .= "&receiverList.receiver(" . $key . ").amount=" . urlencode($value);
}
}
}
if (0 != count($receiverEmailArray))
{
reset($receiverEmailArray);
while (list($key, $value) = each($receiverEmailArray))
{
if ("" != $value)
{
$nvpstr .= "&receiverList.receiver(" . $key . ").email=" . urlencode($value);
}
}
}
if (0 != count($receiverPrimaryArray))
{
reset($receiverPrimaryArray);
while (list($key, $value) = each($receiverPrimaryArray))
{
if ("" != $value)
{
$nvpstr = $nvpstr . "&receiverList.receiver(" . $key . ").primary=" . urlencode($value);
}
}
}
if (0 != count($receiverInvoiceIdArray))
{
reset($receiverInvoiceIdArray);
while (list($key, $value) = each($receiverInvoiceIdArray))
{
if ("" != $value)
{
$nvpstr = $nvpstr . "&receiverList.receiver(" . $key . ").invoiceId=" . urlencode($value);
}
}
}
// optional fields
if ("" != $feesPayer)
{
$nvpstr .= "&feesPayer=" . urlencode($feesPayer);
}
if ("" != $ipnNotificationUrl)
{
$nvpstr .= "&ipnNotificationUrl=" . urlencode($ipnNotificationUrl);
}
if ("" != $memo)
{
$nvpstr .= "&memo=" . urlencode($memo);
}
if ("" != $pin)
{
$nvpstr .= "&pin=" . urlencode($pin);
}
if ("" != $preapprovalKey)
{
$nvpstr .= "&preapprovalKey=" . urlencode($preapprovalKey);
}
if ("" != $reverseAllParallelPaymentsOnError)
{
$nvpstr .= "&reverseAllParallelPaymentsOnError=" . urlencode($reverseAllParallelPaymentsOnError);
}
if ("" != $senderEmail)
{
$nvpstr .= "&senderEmail=" . urlencode($senderEmail);
}
if ("" != $trackingId)
{
$nvpstr .= "&trackingId=" . urlencode($trackingId);
}
/* Make the Pay call to PayPal */
$resArray = hash_call("Pay", $nvpstr);
/* Return the response array */
return $resArray;
}
这是调用前$ nvpstr的值。 Paypal是否可能只是将付款金额作为主要付款?在链式支付的背景下,这没有任何意义。
actionType=PAY¤cyCode=USD&returnUrl=https%3A%2F%2F.com%2Fview_profile.php&cancelUrl=https%3A%2F%2Fexamplefunding.com%2Fview_profile.php&receiverList.receiver(0).amount=95&receiverList.receiver(1).amount=5&receiverList.receiver(0).email=recip_1334204171_biz%40example.com&receiverList.receiver(1).email=example_1334201682_biz%40example.com&receiverList.receiver(0).primary=true&receiverList.receiver(1).primary=false&receiverList.receiver(0).invoiceId=5c4e2902cbe484a0db37284f0144994c&receiverList.receiver(1).invoiceId=6f3d8ce65d1a59b41f8822ba6129ea58&feesPayer=PRIMARYRECEIVER&memo=New+Draft+Lines+-+ExampleFunding.com&senderEmail=paypal_1334201496_per%40example.com&trackingId=mqN8SSgIq
答案 0 :(得分:3)
根据Paypal's Adaptive Payments Documentation:
在链式付款中,发件人向主接收方支付一笔金额, 主接收者从中支付次要接收者。寄件人 只知道主接收器,而不是辅助接收器。
因此,这是按预期工作的。为了向次要接收者支付总金额的5%,我必须改变这一点:
$receiverAmountArray = array(
.05*$backing_amount,
.95*$backing_amount
);
到此:
$receiverAmountArray = array(
.05*$backing_amount,
$backing_amount
);
我错误地认为总量是阵列中各个接收器数量的总和。
答案 1 :(得分:0)
示例:total_amount = 100;
如果我们设置receiverList.receiver(0).primary = true则receiveList.receiver(0).amount = total_amount;
和receiverList.receiver(1).amount = 95%* total_amount