使用C＃在Active Directory中获取用户的父OU

Question

我想检查一个用户是否在特定的父OU中。

我该怎么做？

检查以下代码，明确说明我要查找的内容。

using System.DirectoryServices.AccountManagement;

public bool IsUserInOU(string samAccountName, string OUName){

    using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {                    
                //Check if the user is in the OU specified in OUName
                //Something like:
                //return user.IsInOU(OUName);
            }
         }
}

public void TestIt_1(){
  //The parent OU of this user is "AwesomeOU"
  string samAccountName = "Joe";
  string OUName = "AwesomeOU";
  bool expected = true;
  bool actual = IsUserInOU(samAccountName, OUName);
  Assert.AreEqual(expected, actual);
}

public void TestIt_2(){
  //The parent OU of this user is "WhateverOU"
  string samAccountName = "Mike";
  string OUName = "AwesomeOU";
  bool expected = false;
  bool actual = IsUserInOU(samAccountName, OUName);
  Assert.AreEqual(expected, actual);
}

域名：

• 国家OU
  • 很棒的OU
    • 乔
  • 无论什么OU
    • 麦克

empi回答后的解决方案1 ​​

根据empi提供的信息，我编写了以下方法来提取DistinguishedName中的第一个OU。完成后，其余的都是轻而易举的。

public static string GetOUForUser(string samAccountName)
    {
        using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {
                //System.Console.WriteLine(user.DistinguishedName);
                int startIndex = user.DistinguishedName.IndexOf("OU=", 1) + 3; //+3 for  length of "OU="
                int endIndex = user.DistinguishedName.IndexOf(",", startIndex);
                var group = user.DistinguishedName.Substring((startIndex), (endIndex - startIndex));
                return group;
            }
        }
    }

JPBlanc回答后的解决方案2

public static string GetOUForUser(string samAccountName)
    {
        using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {
                using (DirectoryEntry deUser = user.GetUnderlyingObject() as DirectoryEntry)
                {
                    using (DirectoryEntry deUserContainer = deUser.Parent)
                    {
                        return deUserContainer.Properties["Name"].Value.ToString();
                    }
                }
            }
        }
    }

Answer 1

确定@Empi解决方案正常运行，但UserPrincipal构建于DirectoryEntry个对象上，提供parent或container属性，只为您提供所需的对象，不使用字符串方式。

/* Retreiving a principal context
 */
PrincipalContext domainContext = new PrincipalContext(ContextType.Domain, "WM2008R2ENT:389", "dc=dom,dc=fr", "dom\\jpb", "MyPwd");

/* Retreive a user
 */
UserPrincipal user = UserPrincipal.FindByIdentity(domainContext, "user1");

/* Retreive the container
 */
DirectoryEntry deUser = user.GetUnderlyingObject() as DirectoryEntry;
DirectoryEntry deUserContainer = deUser.Parent;
Console.WriteLine (deUserContainer.Properties["distinguishedName"].Value);

Answer 2

此信息位于UserPrincipal.DistinguishedName。您应该检查DistinguishedName是否以“，”+ ou可分辨名称（不区分大小写）结尾。但是，你必须知道你正在检查的名字。

例如，如果dn为：CN=Jeff Smith,OU=Sales,DC=Fabrikam,DC=COM，则说明用户位于OU=Sales,DC=Fabrikam,DC=COM ou。

Answer 3

这是我如何获取特定AD用户的专有名称，希望它会有所帮助：-）

private static string GetDNOfUser(string user)
{
    var ctx = new PrincipalContext(ContextType.Domain, Environmentals.Domain, Environmentals.OUPath);

    //Creating object for search filter
    UserPrincipal userPrin = new UserPrincipal(ctx)
    {
        //Only getting users with the same name as the input
        Name = user
    };

    var searcher = new PrincipalSearcher
    {
        //Applying filter to query
        QueryFilter = userPrin
    };

    //Finding the user
    var results = searcher.FindOne();
    searcher.Dispose();

    //Return the distinguishedname
    return results.DistinguishedName;
}