我有4个需要加入的列表
public class Person
{
public int personid { get; set; }
public string fname { get; set; }
public string lname { get; set; }
}
public class Department
{
public int depid { get; set; }
public string departmentname { get; set; }
}
public class Group
{
public int groupid { get; set; }
public int depid { get; set; }
public string groupname { get; set; }
}
public class UploadFile
{
public int fileid { get; set; }
public int personid { get; set; }
public int groupid{ get; set; }
public string filename { get; set; }
}
List<Person> Persons=GetPersons();
List<Department> departmentlist=getDepartments();
List<Group> grouplist=getgroups();
List<UploadFile> filelist=getFiles();
我需要一个输出:
fileid fname filename path 1 samplename Mydoc departmentname+">"+groupname
答案 0 :(得分:1)
您可以使用Zip:
List persons=GetPersons();
List departmentlist=getDepartments();
List grouplist=getgroups();
List filelist=getFiles();
var result = persons.Zip(departmentlist, (person, department) => person.fname + " " + department.departmentname)
.Zip(grouplist, (personAndDepartment, group) => personAndDepartment + " " + group.groupName);
// etc ...