Question

有人可以帮助我，我今晚有作业，但有一个绊脚石，因为我似乎没有正确更新JTextArea。循环自己运行并产生6行到consol但不会对GUI做同样的事情？任何建议欢迎。

import java.awt.EventQueue;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.border.EmptyBorder;
import javax.swing.JButton;
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import javax.swing.JTextArea;

@SuppressWarnings("serial")
public class GUI extends JFrame {

private JPanel contentPane;
private JTextArea textField;

/**
 * Launch the application.
 */
public static void main(String[] args) {
    EventQueue.invokeLater(new Runnable() {
        public void run() {
            try {
                GUI frame = new GUI();
                frame.setVisible(true);
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    });
}

/**
 * Create the frame.
 */
public GUI() {
    setTitle("Home Improvement");
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setBounds(100, 100, 666, 300);
    contentPane = new JPanel();
    contentPane.setBorder(new EmptyBorder(5, 5, 5, 5));
    setContentPane(contentPane);
    contentPane.setLayout(null);
    textField = new JTextArea();
    textField.setEditable(false);
    textField.setBounds(5, 5, 655, 235);
    contentPane.add(textField);

    JButton btnClear = new JButton("Clear");
    btnClear.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) 
        {
            textField.setText("");
        }
    });
    btnClear.setBounds(543, 243, 117, 29);
    contentPane.add(btnClear);

    JButton btnProcess = new JButton("Process");
    btnProcess.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent e) 
        {
            populate(); 

        }
    });
    btnProcess.setBounds(414, 244, 117, 29);
    contentPane.add(btnProcess);
}


public void populate() 
{
    String msg = "Error";
    HomeImprovement[] homeImprove = new HomeImprovement[6];
    double price [] = {500.99,33,90,1599,33,900};
    int isWhat [] = {1,0,0,0,1,1};

    homeImprove[0] = new TileInstaller("The Tile Guy\t");
    homeImprove[1] = new Electrician("Electrons R Us\t");
    homeImprove[2] = new HandyMan("Mr. Handy\t");
    homeImprove[3] = new GeneralContractor("N.B.J. Inc.\t");
    homeImprove[4] = new HandyMan("Mr. Handy(Tile)");
    homeImprove[5] = new GeneralContractor("N.B.J. Inc.(Tile)");

    for(int i=0; i<homeImprove.length; i++)
      {
            if ((isWhat[i] != 1))
            {msg=homeImprove[i].doTheElectric();}
            else
            {msg=homeImprove[i].tileIt();}

        String tmp =    "Company: "+homeImprove[i].getCompanyName() + "\t" +
                        "Final Price: "+ homeImprove[i].computeBid(price[i]) + "\t" +
                        "msg: " + msg + "\n";   

        textField.setText(tmp);
      }

}
}

Answer 1

尝试使用摇摆工作者。这个runnable将在ui线程上执行并更新你的UI。

SwingWorker worker = new SwingWorker<ImageIcon[], Void>() {
private String populated = null;
   @Override
   public ImageIcon[] doInBackground() {
      String populated = populate(); //but remove last line and return the result
   }  

   @Override
   public void done() {
      textField.append( populated );
   }
};

Answer 2

你一直在覆盖字符串。

试试这个：

String tmp = "";
for(int i=0; i<homeImprove.length; i++)
{
   if (isWhat[i] != 1)
   {
      msg = homeImprove[i].doTheElectric();
   }
   else
   {
      msg = homeImprove[i].tileIt();
   }

   tmp += "Company: "+homeImprove[i].getCompanyName() + "\t" +
      "Final Price: "+ homeImprove[i].computeBid(price[i]) + "\t" +
      "msg: " + msg + "\n";   

}
textField.setText(tmp);

Btw：我建议改变你的编程风格（我猜你还在学习:-)），换行和缩进不会花费任何成本，并且在搜索错误时会有很多帮助。

Java JTextArea未正确填充。请帮忙

2 个答案: