<PublicRecords>
<USBankruptcies>
<USBanktruptcy>...<USBankruptcy>
<CourtId>...</CourtId>
<USBanktruptcy>...<USBankruptcy>
<CourtId>...</CourtId>
</USBankruptcies>
<USTaxLiens>
<USTaxLien>...<USTaxLien>
<CourtId>...</CourtId>
<USTaxLien>...<USTaxLien>
<CourtId>...</CourtId>
</USTaxLiens>
<USLegalItems>
<USLegalItem><USLegalItem>
<CourtId></CourtId>
<USLegalItem><USLegalItem>
<CourtId></CourtId>
</USLegalItems>
</PubicRecords>
我正在使用doc和xpath对象的组合来提取属性和节点内容。
NodeList bp = doc.getElementsByTagName("USBankruptcy");
NodeList nl = doc.getElementsByTagName("CourtId");
long itrBP;
for (itrBP = 0; itrBP < bp.getLength(); itrBP++ )
{
Element docElement = (Element) bp.item(itrBP);
Element courtElement = (Element) nl.item(itrBP);
NodeList df = docElement.getElementsByTagName("DateFiled");
if(df.getLength() > 0)
{
dateFiled = nullIfBlank(((Element)df.item(0)).getFirstChild().getTextContent());
dateFiled = df.format(dateFiled);
}
但是,当我说获取标签名称CourtID的元素时,它将获得所有CourtID,而不仅仅是USB破产下的那些。
有没有办法指定父母?
我尝试了NodeList nl = doc.getElementsByTagName(“USBankruptcies / CourtId”);
它在运行时给了我一个dom错误。
答案 0 :(得分:1)
请在此处找到代码:
DocumentBuilderFactory domFactory = DocumentBuilderFactory
.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document doc = builder.parse("test.xml");
XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expr = xpath.compile("*//USBankruptcies/CourtId");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
for (int i = 0; i < nodes.getLength(); i++) {
System.out.println(nodes.item(i));
}
答案 1 :(得分:1)
不是在Document上调用getElementsByTagName("CourtId")
方法,而是在子元素(在您的情况下为<USBankruptcies>
元素)上调用它。
NodeList bankruptcyNodes = doc.getElementsByTagName("USBankruptcies");
Element bankruptcyElement = (Element) bankruptcyNodes.item(0);
NodeList bankruptcyCourtNodes = bankruptcyElement.getElementsByTagName("CourtId");
// etc...