Question

我想抓取整个网站，我已经阅读了几个主题，但我无法在第二级获取数据。

也就是说，我可以从起始页面返回链接但是我找不到解析链接并获取每个链接内容的方法......

我使用的代码是：

<?php

    //  SELECT STARTING PAGE
      $url = 'http://mydomain.com/';
      $html= file_get_contents($url);

     // GET ALL THE LINKS OF EACH PAGE

         // create a dom object

            $dom = new DOMDocument();
            @$dom->loadHTML($html);

         // run xpath for the dom

            $xPath = new DOMXPath($dom);


         // get links from starting page

            $elements = $xPath->query("//a/@href");
            foreach ($elements as $e) {
            echo $e->nodeValue. "<br />";
            }

     // Parse each page using the extracted links?

 ?>

有人可以通过一个例子来帮我解决最后一部分吗？

我将非常感激！

嗯，谢谢你的答案！我尝试了一些东西，但我还没有得到任何结果 - 我是编程的新手..

下面，您可以找到我的两次尝试 - 第一次尝试解析链接，第二次尝试用Curl替换file_get内容：

 1) 

<?php 
  //  GET STARTING PAGE
  $url = 'http://www.capoeira.com.gr/';
  $html= file_get_contents($url);

  //GET ALL THE LINKS FROM STARTING PAGE

  // create a dom object

    $dom = new DOMDocument();
    @$dom->loadHTML($html);


    // run xpath for the dom

    $xPath = new DOMXPath($dom);

        // get specific elements from the sites

        $elements = $xPath->query("//a/@href");
//PARSE EACH LINK

    foreach($elements as $e) {
          $URLS= file_get_contents($e);
          $dom = new DOMDocument();
          @$dom->loadHTML($html);
          $xPath = new DOMXPath($dom);
          $output = $xPath->query("//div[@class='content-entry clearfix']");
         echo $output ->nodeValue;
        }                           
         ?>

对于上面的代码，我得到了警告：file_get_contents（）期望参数1为字符串，第26行的../example.php中给出的对象

2）

    <?php
          $curl = curl_init();
          curl_setopt($curl, CURLOPT_POST, 1);
          curl_setopt($curl, CURLOPT_URL, "http://capoeira.com.gr");
          curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
          $content= curl_exec($curl);
          curl_close($curl);    



          $dom = new DOMDocument();
          @$dom->loadHTML($content);

           $xPath = new DOMXPath($dom);
           $elements = $xPath->query("//a/@href");
            foreach ($elements as $e) {
            echo $e->nodeValue. "<br />";
            }

   ?>

我没有结果。我试图回复$ content，然后我得到：

您无权访问此服务器上的/。

此外，尝试使用ErrorDocument处理请求时遇到413 Request Entity Too Large错误...

有什么想法吗？：）

Answer 1

您可以尝试以下操作。有关详细信息，请参阅this thread

<?php
//set_time_limit (0);
function crawl_page($url, $depth = 5){
$seen = array();
if(($depth == 0) or (in_array($url, $seen))){
    return;
}   
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
$result = curl_exec ($ch);
curl_close ($ch);
if( $result ){
    $stripped_file = strip_tags($result, "<a>");
    preg_match_all("/<a[\s]+[^>]*?href[\s]?=[\s\"\']+"."(.*?)[\"\']+.*?>"."([^<]+|.*?)?<\/a>/", $stripped_file, $matches, PREG_SET_ORDER ); 
    foreach($matches as $match){
        $href = $match[1];
            if (0 !== strpos($href, 'http')) {
                $path = '/' . ltrim($href, '/');
                if (extension_loaded('http')) {
                    $href = http_build_url($href , array('path' => $path));
                } else {
                    $parts = parse_url($href);
                    $href = $parts['scheme'] . '://';
                    if (isset($parts['user']) && isset($parts['pass'])) {
                        $href .= $parts['user'] . ':' . $parts['pass'] . '@';
                    }
                    $href .= $parts['host'];
                    if (isset($parts['port'])) {
                        $href .= ':' . $parts['port'];
                    }
                    $href .= $path;
                }
            }
            crawl_page($href, $depth - 1);
        }
}   
echo "Crawled {$href}";
}   
crawl_page("http://www.sitename.com/",3);
?>

Answer 2

$doc = new DOMDocument; 
$doc->load('file.htm'); 

$items = $doc->getElementsByTagName('a'); 

foreach($items as $value) { 
    echo $value->nodeValue . "\n"; 
    $attrs = $value->attributes; 
    echo $attrs->getNamedItem('href')->nodeValue . "\n"; 
};

Answer 3

以递归深度

查找网站链接

<?php


$depth = 1;

print_r(getList($depth));  


function getList($depth)  
{
    $lists = getDepth($depth);
    return $lists; 
 }

function getUrl($request_url)
{
    $countValid = 0;
    $brokenCount =0;
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $request_url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); // We want to get the respone
    $result = curl_exec($ch);
    $regex = '|<a.*?href="(.*?)"|';
    preg_match_all($regex, $result, $parts);
    $links = $parts[1];
    $lists = array();
    foreach ($links as $link)
    {
        $url = htmlentities($link);
        $result =getFlag($url);
        if($result == true)
        {
            $UrlLists["clean"][$countValid] =$url;
            $countValid++; 
        } 
        else
        {
            $UrlLists["broken"][$brokenCount]= "broken->".$url;
            $brokenCount++;
        }  

    }
    curl_close($ch);
    return $UrlLists;
}
function ZeroDepth($list)
{
    $request_url = $list;
    $listss["0"]["0"] = getUrl($request_url);
    $lists["0"]["0"]["clean"] = array_unique($listss["0"]["0"]["clean"]);
    $lists["0"]["0"]["broken"] = array_unique($listss["0"]["0"]["broken"]);
    return $lists; 
}

function getDepth($depth)
{        
   // $list =OW_URL_HOME;
    $list = "https://example.com";//enter the url of website 
    $lists =ZeroDepth($list);
    for($i=1;$i<=$depth;$i++)
    {
        $l= $i;
        $l= $l-1;
        $depthArray=1;
        foreach($lists[$l][$l]["clean"] as $depthUrl)
        { 
            $request_url = $depthUrl;
            $lists[$i][$depthArray]["requst_url"]=$request_url;
            $lists[$i][$depthArray] = getUrl($request_url);

        }  

    }
    return $lists;   
}

function getFlag($url) 
{
    $url_response = array();
    $curl = curl_init();
    $curl_options = array();
    $curl_options[CURLOPT_RETURNTRANSFER] = true;
    $curl_options[CURLOPT_URL] = $url;
    $curl_options[CURLOPT_NOBODY] = true;
    $curl_options[CURLOPT_TIMEOUT] = 60;
    curl_setopt_array($curl, $curl_options);
    curl_exec($curl);
    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE);
    if ($status == 200) 
    { 
        return true;
    } 
    else 
    {
        return false;
    }
    curl_close($curl);
}
?>`

Answer 4

请检查下面的代码，希望对您有帮助。

<?php
$html = new DOMDocument();
@$html->loadHtmlFile('http://www.yourdomain.com');
$xpath = new DOMXPath( $html );
$nodelist = $xpath->query( "//div[@class='A-CLASS-Name']/h3/a/@href" );
foreach ($nodelist as $n){
    echo $n->nodeValue."\n<br>";
}
?>

谢谢，罗杰

Answer 5

<?php
$path='http://www.hscripts.com/';
$html = file_get_contents($path);
$dom = new DOMDocument();
@$dom->loadHTML($html);
// grab all the on the page
$xpath = new DOMXPath($dom);
$hrefs = $xpath->evaluate("/html/body//a");
for ($i = 0; $i < $hrefs->length; $i++ ) {
$href = $hrefs->item($i);
$url = $href->getAttribute('href');
echo $url.'<br />';
}
?>

您可以使用上面的代码获取所有可能的链接

抓取网站，获取链接，使用PHP和XPATH抓取链接

5 个答案: