我正在iPhone上做一个项目。在这里,我必须向Web服务发送POST请求。我使用NSMutableURLRequest和NSURLConnection发送数据,服务器使用PHP。我发现检查if ($_SERVER['REQUEST_METHOD'] != "POST")
总是失败,就像返回'GET'一样,即使我在localhost上尝试它。
我的POST请求如下(通过Wireshark嗅探):
POST tester.php HTTP/1.1
Host: localhost
User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:10.0.2) Gecko/20100101 Firefox/10.0.2
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip, deflate
Connection: keep-alive
Referer: http://localhost/tester.php
Content-Type: application/x-www-form-urlencoded
Content-Length: 422
protocol=4&msgtype=authorize&merchant=86189919&language=da&ordernumber=1274168351&amount=100¤cy=DKK&continueurl=http%3A%2F%2Fquickpay.net%2Ffeatures%2Fpayment-window%2Fok.php&cancelurl=http%3A%2F%2Fquickpay.net%2Ffeatures%2Fpayment-window%2Ferror.php&callbackurl=http%3A%2F%2Fquickpay.net%2Ffeatures%2Fpayment-window%2Fcallback.php&autocapture=0&cardtypelock=&splitpayment=1&md5check=d2259d9db077e0f5a41b4bf271c3c549
当然,那里有很多虚拟文本,通常不会出现在iPhone上,但我试图通过html表单进行相同的调用,这很有效。因此,我已经复制了所有信息,看看这是否有所作为,但无济于事。
我比较了两个请求(一个来自iPhone,另一个来自我的php页面),它们看起来完全一样。
我大吃一惊 - 有没有人对如何做有很好的建议?
修改
你的测试不测试post或post vs get,它专门测试POST,你可能有一个案例问题......你试过在php中检查请求本身吗? - 格雷迪球员
是的,这可能是真的,但该行总是返回GET,因此案例问题已经涵盖,如果这就是你的意思。
另外,当iPhone发送请求时,请从服务器发布print_r($ _ SERVER)的结果 - Aleks G
数组(HTTP_HOST => 10.11.105.254 HTTP_USER_AGENT => Mozilla / 5.0(iPhone模拟器; CPU iPhone OS 5_1,如Mac OS X)AppleWebKit / 534.46(KHTML,类似Gecko)Mobile / 9B176 HTTP_ACCEPT => text / html,application / xhtml + xml,application / xml; q = 0.9, / ; q = 0.8 HTTP_ACCEPT_LANGUAGE => en-us HTTP_ACCEPT_ENCODING => gzip,deflate HTTP_CONNECTION => keep-alive PATH => / usr / bin:/ bin:/ usr / sbin:/ sbin SERVER_SIGNATURE => Apache / 2.2.21(Unix)DAV / 2 PHP / 5.3.8 with Suhosin-Patch Server at 10.11.105.254 Port 80 SERVER_SOFTWARE => Apache / 2.2.21(Unix)DAV / 2 PHP / 5.3.8与Suhosin-Patch SERVER_NAME => 10.11.105.254 SERVER_ADDR => 10.11.105.254 SERVER_PORT => 80 REMOTE_ADDR => 10.11.105.254 DOCUMENT_ROOT => / Library / WebServer / Documents SERVER_ADMIN => you@example.com SCRIPT_FILENAME => /Users/tester.php REMOTE_PORT => 51492 GATEWAY_INTERFACE => CGI / 1.1 SERVER_PROTOCOL => HTTP / 1.1 REQUEST_METHOD => GET QUERY_STRING => REQUEST_URI => /tester.php SCRIPT_NAME => /tester.php PHP_SELF => /tester.php REQUEST_TIME => 1334211212 argv => Array argc => 0)
您是否尝试检查是否有已知变量,例如是否设置了$ _POST ['known_to_be_set_by_client']?如果请求是POST或GET,那不是PHP,它是Web服务器。 - Tim Post
当我尝试从iPhone请求中回显已知变量时,它当然是空的。这是有道理的。当我从表格中回应同样的东西时,它就在那里。
发布您使用的iOS代码以发出实际请求。 - Cliff Ribaudo
以下是创建请求并发送请求的代码:
//variables
NSString *protocol = @"4";
NSString *msgtype = @"authorize";
NSString *merchant = @"86189919";
NSString *language = @"da";
NSString *orderNo = @"1274168351";
NSString *amount = @"100";
NSString *currency = @"DKK";
NSString *continueURL = @"http://quickpay.net/features/payment-window/ok.php";
NSString *cancelURL = @"http://quickpay.net/features/payment-window/error.php";
NSString *callbackURL = @"http://quickpay.net/features/payment-window/callback.php";
NSString *autoCapture = @"0";
NSString *cardtypeLock =@"";
NSString *splitText = @"1";
NSString *md5check = @"d2259d9db077e0f5a41b4bf271c3c549";
//setting up the request
NSMutableString *post = [[NSMutableString alloc] initWithString:@"protocol="];
[post appendString:protocol];
[post appendString:@"&msgtype="];
[post appendString:msgtype];
[post appendString:@"&merchant="];
[post appendString:merchant];
[post appendString:@"&language="];
[post appendString:language];
[post appendString:@"&ordernumber="];
[post appendString:orderNo];
[post appendString:@"&amount="];
[post appendString:amount];
[post appendString:@"¤cy="];
[post appendString:currency];
[post appendString:@"&continueurl="];
[post appendString:continueURL];
[post appendString:@"&cancelurl="];
[post appendString:cancelURL];
[post appendString:@"&callbackurl="];
[post appendString:callbackURL];
[post appendString:@"&autocapture="];
[post appendString:autoCapture];
[post appendString:@"&cardtypelock="];
[post appendString:cardtypeLock];
[post appendString:@"&splitpayment="];
[post appendString:splitText];
[post appendString:@"&md5check="];
[post appendString:md5check];
//escape characters
NSString *tmp = (__bridge NSString *)CFURLCreateStringByAddingPercentEscapes(
NULL,
(__bridge CFStringRef)post,
NULL,
(CFStringRef)@";/:@+$,~",
kCFStringEncodingUTF8
);
NSData *body = [tmp dataUsingEncoding:NSUTF8StringEncoding];
//setup url
NSString *urlString =@"http://10.10.225.255/tester.php";
NSURL *quickUrl = [NSURL URLWithString:urlString];
//setup URL request
NSMutableURLRequest *request = [[NSMutableURLRequest alloc]init];
//method
[request setHTTPMethod:@"POST"];
//url
[request setURL:url];
//body data to string
NSString *strData = [[NSString alloc]initWithData:body encoding:NSUTF8StringEncoding];
//content length
NSString *postLenght = [NSString stringWithFormat:@"%d", [body length]];
//set body
[request setHTTPBody:body];
//Dummy data to make the request look like the same from the HTML form.
[request setValue:@"localhost" forHTTPHeaderField:@"Host"];
[request setValue:@"Mozilla/5.0 (Macintosh; Intel Mac OS X 10.7; rv:10.0.2) Gecko/20100101 Firefox/10.0.2" forHTTPHeaderField:@"User-Agent"];
[request setValue:@"text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" forHTTPHeaderField:@"Accept"];
[request setValue:@"en-us,en;q=0.5" forHTTPHeaderField:@"Accept-Language"];
[request setValue:@"gzip, deflate" forHTTPHeaderField:@"Accept-Encoding"];
[request setValue:@"http://localhost/tester.php" forHTTPHeaderField:@"Referer"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setValue:postLenght forHTTPHeaderField:@"content-length"];
//send the request to server
if([[NSURLConnection alloc] initWithRequest:request delegate:self]){
NSLog(@"sending data to quickpay");
}
答案 0 :(得分:1)
(这是评论而不是答案)如果
if ($_SERVER['REQUEST_METHOD'] != "POST")
总是失败(正如你在问题中写的那样),这必须意味着:
$_SERVER['REQUEST_METHOD'] == "POST"
因此,您要么提出了错误的问题,要么您没有正确验证输入值。请将var_dump($_SERVER)
的输出添加到您的问题中。
答案 1 :(得分:0)
我明白了。 正如所料,这是我自己的疏忽! 当我将url加载到UIWebView中时,在委托中,我使用了loadRequest方法,该方法当然使用GET请求来返回内容。相反,我应该使用loadHTMLString:baseURL:方法来加载返回的数据。 此错误意味着应用程序在我的初始POST后发出了另一个GET请求,从而导致错误。很明显,我没有注意到这个额外的时间请求。