Question

我已经在这一段时间了，似乎无法解决这个问题。这就是我想要做的。给定三个单词word1，word2和word3，我想构建一个正则表达式，它将按顺序匹配它们，但它们之间有一组潜在的单词（新行除外）。

例如，如果我有以下内容：

word1 = what
word2 = the
word3 = hell

我想匹配以下字符串，只需一个匹配：

"what the hell"
"what in the hell"
"what the effing hell"
"what in the 9 doors of hell"

我认为我可以执行以下操作（允许每个单词变量之间存在0到5个单词）：

regex = "\bword1(\b\w+\b){0,5}word2(\b\w+\b){0,5}word3\b"

唉，不，它不起作用。重要的是我有办法在单词之间指定m到n的单词距离（其中m总是＆lt; n）。

Answer 1

"\bwhat(\s*\b\w*\b\s*){0,5}the(\s*\b\w*\b\s*){0,5}hell"适合我（在Ruby中）

list = ["what the hell", "what in the hell", "what the effing hell", 
  "what in the 9 doors of hell", "no match here hell", "what match here hell"]

list.map{|i| /\bwhat(\s*\b\w*\b\s*){0,5}the(\s*\b\w*\b\s*){0,5}hell/.match(i) }
=> [#<MatchData:0x12c4d1c>, #<MatchData:0x12c4d08>, #<MatchData:0x12c4cf4>,
   #<MatchData:0x12c4ce0>, nil, nil]

Answer 2

$ cat try
#! /usr/bin/perl

use warnings;
use strict;

my @strings = (
  "what the hell",
  "what in the hell",
  "what the effing hell",
  "what in the 9 doors of hell",
  "hello",
  "what the",
  " what the hell",
  "what the hell ",
);

for (@strings) {
  print "$_: ", /^what(\s+\w+){0,5}\s+the(\s+\w+){0,5}\s+hell$/
                  ? "match\n"
                  : "no match\n";
}

$ ./try
what the hell: match
what in the hell: match
what the effing hell: match
what in the 9 doors of hell: match
hello: no match
what the: no match
 what the hell: no match
what the hell : no match

Answer 3

在clojure中为我工作：

(def phrases ["what the hell" "what in the hell" "what the effing hell"
              "what in the 9 doors of hell"])

(def regexp #"\bwhat(\s*\b\w*\b\s*){0,5}the(\s*\b\w*\b\s*){0,5}hell")

(defn valid? []
  (every? identity (map #(re-matches regexp %) phrases)))

(valid?)  ; <-- true

根据Ben Hughes的模式。

RegEx - 匹配一组单词

3 个答案: